- #1
j3dwards
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Homework Statement
The circuit consists of three identical light bulbs and two identical coils, connected to a DC current source.
The ohmic resistance of the coils is negligible. The system is left to settle into a steady state and then the switch S is opened. Describe and explain in as much detail as you can the brightness of the bulbs shortly after the switch is opened.
Homework Equations
V=IR?
The Attempt at a Solution
I think this is more a worded question rather than involving equations.
So I'm thinking that after the switch is opened, no more current can flow. But the current that has just left the current source, which is passing through the coils, still moves until the charge has completed its circuit and moved to the negative terminal (or in actual fact electrons move from negative to positive - but I'm considering the conventional case). So does this mean that the light bulbs still all remain at equal brightness until the current has passed?
Please help!