Circuit to control a full wave via single SCR

In summary, the voltage coming out of the bridge rectifier is stable and does not have a SCR affect on the shape of the output signal.
  • #1
Femme_physics
Gold Member
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1

Homework Statement



http://img543.imageshack.us/img543/7906/ddd2e.jpg

To translate from Hebrew from left to right: Net Voltage 220 Vac, Pull Down Transformer, full wave rectifier (marked with a, b, c, d), below it is a "load" (or resistance), and to the right it says "a circuit to control the angel of ignition".

The Attempt at a Solution



I am first asked to draw a full rectifier that includes 4 rectifying diodes, and include where "a", "b", "c", and "d" is there.

Did I get it?

http://img859.imageshack.us/img859/2743/ddd1s.jpg
 
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  • #2
Hi FP :smile:
Something looks amiss in your attempt.
Look where your input is to the full bridge rectifier (first diagram).
(input is coming from the secondary winding of the transformer)
How is it labelled? Do you see the corresponding position in your
second diagram for the input signal?
(hint, you haven't labelled those points yet).

When you say pull-down transformer, i would expect the voltage
at the secondary winding is lower than the primary voltage. In your
second diagram you show the input to the rectifier the same as the
primary voltage (220-230V)

On the output side, your d is labelled correctly, but the other
side of the load resistor is not b. Do you see what it should be?
(see first diagram).

You may notice you have indicated a & d at the same node
in your circuit. Did you really mean to do that?

I suggest looking up full wave bridge rectifier (FWBR) on the web.
There is a more standard representation of the diodes in a FWBR that makes it
a whole lot simpler to analyze in a circuit.
(hint: see 2nd circuit diagram (with 4 diodes) on the link i gave).
 
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  • #3
When you say pull-down transformer, i would expect the voltage
at the secondary winding is lower than the primary voltage. In your
second diagram you show the input to the rectifier the same as the
primary voltage (220-230V)

The pull-down transformer is 10:1 but they only let me know that in the second part of the question. The first part just wants me to figure out the rectifier circuit.

Hi FP
Something looks amiss in your attempt.
Look where your input is to the full bridge rectifier (first diagram).
(input is coming from the secondary winding of the transformer)
How is it labelled? Do you see the corresponding position in your
second diagram for the input signal?
(hint, you haven't labelled those points yet)

I'm pretty sure I follow you. I see a is the positive end and b is the negative end. As far as the outputs-- "d" I'm glad you confirmed because it made sense to me even when rethinknig the problem. And as far as "c", it makes sense to me it's just the other end of the load.

http://img209.imageshack.us/img209/148/ablast.jpg
 
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  • #4
Looks good.

(Quick eh? :wink:)
 
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  • #5
LOL, insanely quickly!

Now the second question wants me to draw a graph with an appropriate scale of the voltage the falls on the load, while mentioning voltages and times.

The transformer reduces the net voltage at a 1:10 relaton
Alpha (the ignition angle) is 40 degrees
The net voltage acts in frequency of 50 hertz

http://img811.imageshack.us/img811/6298/vppg.jpg

In the graph, alpha = 40 degrees, beta = 140 degrees

Url max is same as Vt max
 
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  • #6
Nice Job (on part 1)! :approve:

on part 2:
What is the behavior of the voltage coming out of the Bridge Rectifier?
I don't see that in your graphs.

Do you know what affect the SCR has, on the shape of the output signal?
Once you fix the graph of the rectified voltage, the "on" voltages you've indicated look fine. :smile:

If you're saying the amplitude of voltage = [itex]Vpp\sqrt{22}[/itex], I don't figure that.
(Hint: you have Vrms = 22V)

I agree, the period ([itex]\tau[/itex]) of the signal at frequency of 50Hz equals 0.02sec,
but your graph does not indicate that.
(Hint: what part of a period does [itex]\alpha+\beta[/itex] equal?)
 
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  • #7
My bad, I meant 22(Square root)2, not square root of 22... *slaps forehead*

What is the behavior of the voltage coming out of the Bridge Rectifier?
I don't see that in your graphs.

Do you know what affect the SCR has, on the shape of the output signal?
Once you fix the graph of the rectified voltage, the "on" voltages you've indicated look fine.

You're right, it doesn't let current go through the negative end. Besides, the rectificer assures there is only pulse on the positive end...ah... I see what I did wrong now.

I agree, the period (τ) of the signal at frequency of 50Hz equals 0.02sec,
but your graph does not indicate that.
(Hint: what part of a period does α+β equal?)

Alpha and beta only apply to the positive period, because it's the only period that existsI'll fix it with graphs soon :)
 
  • #8
Femme_physics said:
My bad, I meant 22(Square root)2, not square root of 22... *slaps forehead*
Good !
You're right, it doesn't let current go through the negative end. Besides, the rectificer assures there is only pulse on the positive end...ah... I see what I did wrong now.
sounds like you're on a roll. :smile:
Alpha and beta only apply to the positive period, because it's the only period that exists
Well a full period equals 360 degrees, whether voltages are positive or negative.
You've already stated the values of [itex]\alpha[/itex] and [itex]\beta[/itex], which is useful in this context.

Trivia: we sometimes use ג,ב,א as variables.. I've noticed them in a few engineering texts :smile:
 
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  • #9
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  • #10
(א) I agree with D1 D4 on the Positive half cycle. However I disagree with
the diodes that you chose to conduct the negative half cycle.
(Hint: look in the reference I gave you in post #2).

(ב) How come you have [itex]\sqrt{22} [/itex] on your graph again?
You told me the correct peak voltage in post #7.
I take it you understand how an SCR affects output voltage across a load, from previous material.
That part looks good, where it cuts off and on.
The shape of the output voltage also looks much better. Is that all they ask?
You may also want to label the peak voltage on the U_RL plot.
The x-axis labeling looks great!

(ג) Looks interesting, were you given the equation for this part, or did you derive it?
Given the equation you used; I plugged in the numbers we found for this example
and came out with the same numerical result.

Really? Where? That's pretty funny.. I've never seen cyrillic or hindu alphabets used for unknowns.
I can't remember exactly where, but when I mentioned it to some friends, they tell me they also had seen Hebrew characters in some texts. Now Hindi would be some interesting variables: ह, ज, क ..:smile:
 
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  • #11
Sorry-- I miswrote, it's D2 and D3. :)
 
  • #12
Femme_physics said:
Sorry-- I miswrote, it's D2 and D3. :)

Yep :)
 

1. How does an SCR work in a full wave circuit?

An SCR (Silicon Controlled Rectifier) is a semiconductor device that acts as a switch in an electrical circuit. It allows current to flow in one direction when a small gate current is applied, and then continues to conduct even after the gate current is removed. In a full wave circuit, the SCR controls the flow of alternating current (AC) by only allowing current to pass during specific parts of the AC cycle.

2. What components are needed for a circuit to control a full wave via single SCR?

In addition to the SCR, a full wave circuit typically requires a transformer, diodes, and a load. The transformer steps down the AC voltage from the power source, while the diodes convert the AC to pulsating DC. The SCR then controls the flow of this DC current to the load.

3. How is the gate signal applied to the SCR in a full wave circuit?

The gate signal is typically applied through a resistive or capacitive circuit, which limits the amount of current that reaches the gate. This is necessary because too much current can damage the SCR. The gate signal is typically synchronized with the AC cycle to ensure that the SCR only conducts during the desired part of the cycle.

4. What is the advantage of using a single SCR in a full wave circuit?

Using a single SCR in a full wave circuit is more efficient and cost-effective compared to using multiple SCRs. It also simplifies the circuit design and reduces the number of components needed.

5. Are there any limitations to using an SCR in a full wave circuit?

One limitation of using an SCR in a full wave circuit is that it can only control the flow of current in one direction. This means that the load being powered must also be able to operate with pulsating DC current. Additionally, the SCR may generate heat and require proper cooling to prevent damage.

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