Circular motion - Which string breaks first?

In summary, the main factors that determine which string will break first in circular motion are the tension and strength of the material used in the strings. The speed of the circular motion can also play a role, as well as other variables such as the length of the strings, angle of pulling, imperfections, and external forces. Additionally, the direction of the circular motion can also impact which string breaks first.
  • #1
Raishiin
1
0

Homework Statement


Basically, three different masses hanging on three strings of different lengths all different distances from the axis of rotation. They have a maximum tensile strength of 450 Newtons. I have to solve in variable form first, and however... Well, okay. Just check the image below.

http://i44.tinypic.com/ae4egk.jpg

I just need to find an equation where I can vary the rotational speed and solve for the tension. Despite what I show in the image, for step two I really seem to need an equation where when given all the variables you can solve the function by changing "N" until you see it hits 450 Newtons and the string breaks. The angle theta changes the radius which changes the velocity which then changes the acceleration and centripetal force so things just go bad really fast for me.

Homework Equations


v = (2piR/N)
a = v^2/r
F(c) = mv^2/r

The Attempt at a Solution


Well, based on the image I drew and posted... The corrected radius is the original radius plus the string length multiplied by the sin of theta. Using all that I wind up finding two functions from that picture that I think could apply for the tensions... But I'm making a screwy mistake somewhere in one of these. (m*g*cos(theta) or just m*g the whole time?)

T = mgcos(theta) + 4mpi^2(R+Lsin(theta)/N^2 = 450
Or
T = mg + 4mpi^2(R+Lsin(theta))/N^2 = 450

If anyone can help me, that'd be great. I feel like such an idiot because this was on my last test. (Though my professor honestly didn't prepare us for questions like this. None of the homework or worksheets was nearly this hard... -_-)

Oh! I accidentally labeled the opposite "H" in the diagram. I meant to say "O" for opposite. My bad...
 
Last edited:
Physics news on Phys.org
  • #2

It seems like you are trying to find an equation that relates the rotational speed, tension, and other variables in this system. First, make sure you have a clear understanding of the variables involved and their relationships. From the diagram, it looks like the system consists of three masses hanging on strings of different lengths, with a maximum tensile strength of 450 Newtons. The angle theta changes the radius, which affects the velocity, acceleration, and centripetal force.

In order to find an equation that relates all of these variables, you can use the equations you listed in the "Homework Equations" section. The first equation, v = (2piR/N), relates the rotational speed (N) to the radius (R). The second equation, a = v^2/r, relates the velocity (v) to the acceleration (a) and radius (r). And the third equation, F(c) = mv^2/r, relates the mass (m), velocity (v), and radius (r) to the centripetal force (F(c)).

Using these equations, you can manipulate them to solve for the tension (T) in terms of the other variables. For example, using the third equation, you can solve for T by setting F(c) = 450 Newtons and substituting in the values for m, v, and r in terms of the other variables. This will give you an equation that relates T to N, R, and theta. You can also try using the first two equations together to eliminate the velocity and solve for T in terms of N, R, and theta.

It's important to carefully consider the units and make sure they are consistent throughout your equations. Also, make sure you are using the correct values for the variables, as it looks like there may be some confusion with the labels in your diagram.

I hope this helps and good luck with your problem solving! Remember, practice makes perfect and don't be too hard on yourself if you make mistakes. We all learn from our mistakes and they help us improve. Keep up the good work!
 

1. What factors determine which string will break first in circular motion?

The main factors that determine which string will break first in circular motion are the tension in each string and the strength of the material used to make the strings. The higher the tension and the weaker the material, the more likely the string is to break.

2. Does the speed of the circular motion affect which string will break first?

Yes, the speed of the circular motion can play a role in which string breaks first. The faster the speed, the higher the tension in the strings, which can increase the chances of one of the strings breaking.

3. Is the length of the strings a factor in determining which one will break first?

The length of the strings can affect which one breaks first, but it is not the main determining factor. The tension and strength of the strings are more important in this scenario.

4. Are there any other variables that may impact which string breaks first?

Other variables that may impact which string breaks first include the angle at which the strings are pulled, any imperfections or weak points in the strings, and external forces acting on the strings.

5. Can the direction of the circular motion affect which string breaks first?

Yes, the direction of the circular motion can have an impact on which string breaks first. For example, if one string is being pulled in the opposite direction of the other, it may experience more tension and have a higher chance of breaking.

Similar threads

  • Introductory Physics Homework Help
Replies
14
Views
2K
  • Introductory Physics Homework Help
Replies
19
Views
1K
  • Introductory Physics Homework Help
Replies
11
Views
2K
  • Introductory Physics Homework Help
2
Replies
55
Views
670
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
3K
  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
9
Views
3K
  • Introductory Physics Homework Help
Replies
2
Views
683
Back
Top