- #1
Ken Gallock
- 30
- 0
Homework Statement
Consider gamma matrices ##\gamma^0, \gamma^1, \gamma^2, \gamma^3## in 4-dimension. These gamma matrices satisfy the anti-commutation relation
$$
\{ \gamma^\mu , \gamma^\nu \}=2\eta^{\mu \nu}.~~~(\eta^{\mu\nu}=diag(+1,-1,-1,-1))
$$
Define ##\Gamma^{0\pm}, \Gamma^{1\pm}## as follows:
\begin{align}
\Gamma^{0\pm}:=\dfrac12 (\gamma^0 \pm \gamma^1),\\
\Gamma^{1\pm}:=\dfrac12 (i\gamma^2 \pm \gamma^3).
\end{align}
They satisfy following anti-commutation relations.
$$
\{ \Gamma^{a+}, \Gamma^{b-} \}=\delta^{ab},
\{ \Gamma^{a+}, \Gamma^{b+} \} = \{ \Gamma^{a-}, \Gamma^{b-} \}=0.
~~(a,b=0,1)
$$
Now, we can construct other Clifford algebra in higher dimensions.
Question: Construct Clifford algebra for 1+10 dimension and 2+10 dimension as we did in above.
Homework Equations
The Attempt at a Solution
The reason this problem is difficult for me is that 1+10 dimension is 11-dimension space-time and they are odd number dimension. If it were even number dimension, then it is easy to construct Clifford algebra; we only have to add new terms such like
$$
\Gamma^{2\pm}=\dfrac12 (i\gamma^3 \pm \gamma^4).
$$
But in 11-dimension, we can't do this. I tried to think in 3-dimension, but I couldn't figure out how to construct Clifford algebra.
Thanks.