Compressible choked gas flow through an orifice -- Excel formula

In summary, the conversation discusses the problem of modeling the flow through an orifice with specific parameters such as upstream and downstream pressure, diameter of the orifice, and type of gas. The speaker explains their attempts at calculating the flow rate using equations and formulas, but encounters difficulties with the sonic flow calculation. They also mention the unexpected result of decreasing pressure resulting in the same volumetric flow rate. The speaker hopes for assistance in finding and correcting any mistakes in their calculations.
  • #1
stuartsjg
1
1
Hello,

I normally get these things working but I am a bit stuck as i don't feel I am getting sensible answers...

The problem is simple (!):
Q: Model the flow through an orifice with an upstream/supply pressure of 301BarA where the downstream pressure is in the range 1BarA to 301BarA. The orifice is 0.5mm in diameter and gas is Helium at 0C​

I am doing this in excel so formula are what I've copied out of that. I have:
P0 as 301BarA​
P1 as 1 to 301BarA​
T1 as 0C​
>> Determined density as p0 =((4*P0)/(0.0821*(T1+273)))/1000/1000 to get kG/cu.m so i get 5.35396E-05 which i believe to be correct.​
(checked at 1BarA aligns with textbook values)​
cp as 5.193​
cv as 3.116​
>> Determined specific heat ratio as y = 1.6667 which aligns with textbook values​
>> Determined p* as =(2/(y+1))^(y/(y-1)) which for helium is 0.487 which i think is OK too​
Critical pressure CP* = P1 / p*​
>> For example, with a P1 of 100BarA i get the critical pressure as CP* = 205.28BarA​
Determining sonic flow by p1/p2 and where p1 is greater than the critical pressure (else subsonic)​
>> eg 200BarA into 96BarA is supersonic flow as 200Bar is greater than (P2/p*) 96/0.487 = 197BarA​
but 200BarA into 104BarA is subsonic flow as 200Bar is less than 213.49BarA​
From this, i have a column which is intended for a sonic mass flow calculation and another for subsonic, and just an IF statement to use the appropriate calculation for the final result.​
Finally, the orifice is defined as​
Cd = 0.6 (arbitrary typical number)​
SupplyDia = 5mm (upstream pipe diameter)​
OrificeDia = 0.5mm >> calculated as 1.9635E-07 sq.m​

So, i think I've been successful in doing the subsonic flow, engineering toolbox has a calculator for this and my numbers align.
For reference, I've worked this out by:
mass flow kG/S mdot = Cd*(PI()/4)*((OrificeDia/1000)^2)*p0*(2*(((P0-P1)*100000))/(p0*(1-(OrificeDia/SupplyDia)^4)))^0.5​

As an example:
P0 = 200BarA, P1 = 160BarA​
>> mass flow mdot = 1.99086E-06 kG/s which i convert to volumetric by =(mdot/p0)*1000*60 or 3346.6 L/min​

Putting a practical head on, i can picture that sort of flow rate for that pressure and nozzle etc.

Going for a pressure closer to the critical point, just as we fall out of sonic flow, i get we should be looking at not too much over
3.16458E-06 kG/sec 5319.65L/min - however any way i try to implement the sonic calculations, i get wildly different answers!

What I've tried(!):
From engineering tool box (no calc for this, just eqn)​
mdot = (Cd*OrificeArea)*(SQRT(y*p0*P0*((2/y+1)^((y+1)/(y-1)))))​
>> Given the same just at the critical point entering into sonic flow, this gives mdot = 6.21982E-08 kG/se or 104.55L/min which i feel too low​
from chemeurope, a version which didnt need the density​
mdot = =(Cd*OrificeArea*P0*100000)*SQRT(((y*4.003)/((1+0.0045*0.1*P0)*8314.5*(T0+273)))*(2/(y+1))^((y+1)/(y-1)))​
>> this gives a result of 0.00218 kG/s or 3,658,503.09 L/min which is certainly too high!​
Ive done a bit of a cheat in excel which is to determine the highest mass flow rate (using the sub-sonic calculation) before we enter sonic flow, on the basis just before sonic flow and just after sonic flow are not going to be a million miles different.

This is a bit of a cheat as i would really like to get my sonic flow calculation correct and working.

One other odd effect i had not expected...

Using the sub-sonic flow method as described, it doesn't matter what input pressure P0 i have, whether its 10bar or 300bar, i always get the same volumetric flow rate, but a different mass flow rate, for example:

P0P1m (total)volumetricP0P1m (total)volumetricP0P1m (total)volumetricP0P1m (total)volumetric
BarABarAkg/secL/minBarABarAkg/secL/minBarABarAkg/secL/minBarABarAkg/secL/min
300​
126​
4.7469E-06​
5319.650936​
200​
84​
3.16E-06​
5319.651​
100​
42​
1.58E-06​
5319.651​
50​
21​
7.91E-07​
5319.651​
300​
132​
4.7469E-06​
5319.650936​
200​
88​
3.16E-06​
5319.651​
100​
44​
1.58E-06​
5319.651​
50​
22​
7.91E-07​
5319.651​
300​
138​
4.7469E-06​
5319.650936​
200​
92​
3.16E-06​
5319.651​
100​
46​
1.58E-06​
5319.651​
50​
23​
7.91E-07​
5319.651​
300​
144​
4.7469E-06​
5319.650936​
200​
96​
3.16E-06​
5319.651​
100​
48​
1.58E-06​
5319.651​
50​
24​
7.91E-07​
5319.651​
300​
150​
4.7217E-06​
5291.478222​
200​
100​
3.15E-06​
5291.478​
100​
50​
1.57E-06​
5291.478​
50​
25​
7.87E-07​
5291.478​
300​
156​
4.6263E-06​
5184.568651​
200​
104​
3.08E-06​
5184.569​
100​
52​
1.54E-06​
5184.569​
50​
26​
7.71E-07​
5184.569​
300​
162​
4.5289E-06​
5075.407612​
200​
108​
3.02E-06​
5075.408​
100​
54​
1.51E-06​
5075.408​
50​
27​
7.55E-07​
5075.408​
300​
168​
4.4294E-06​
4963.846569​
200​
112​
2.95E-06​
4963.847​
100​
56​
1.48E-06​
4963.847​
50​
28​
7.38E-07​
4963.847​
300​
174​
4.3275E-06​
4849.719898​
200​
116​
2.89E-06​
4849.72​
100​
58​
1.44E-06​
4849.72​
50​
29​
7.21E-07​
4849.72​
300​
180​
4.2232E-06​
4732.842002​
200​
120​
2.82E-06​
4732.842​
100​
60​
1.41E-06​
4732.842​
50​
30​
7.04E-07​
4732.842​
300​
186​
4.1163E-06​
4613.003766​
200​
124​
2.74E-06​
4613.004​
100​
62​
1.37E-06​
4613.004​
50​
31​
6.86E-07​
4613.004​
300​
192​
4.0065E-06​
4489.96816​
200​
128​
2.67E-06​
4489.968​
100​
64​
1.34E-06​
4489.968​
50​
32​
6.68E-07​
4489.968​

I think the effect of the decreasing pressure P0 reducing the density is cancelling out the conversion from gravimetric to volumetric, although i would have thought less pressure = less density (OK) = less mass (OK) = less flow (not OK)... So that's probably an issue!

Anyway, I've attached the spreadsheet I am working on, sorry its a bit of a work in progress!

Sorry for the long question, i am hoping there's just a few simple mistakes in there... :)

Any help would be appreciated - its consumed an evening with much head scratching, i even asked my 5 year old Daughter and told me "stop being silly" and walked away...

Thanks,
Stuart G
 

Attachments

  • OrificeFlow.xlsx
    46.4 KB · Views: 168
  • Like
Likes FluidDroog
Science news on Phys.org
  • #2
Hi Stuart,

Let's get to the bottom of this.
P0 as 301BarA
P1 as 1 to 301BarA
T1 as 0C
>> Determined density as p0 =((4*P0)/(0.0821*(T1+273)))/1000/1000 to get kG/cu.m so i get 5.35396E-05 which i believe to be correct.
(checked at 1BarA aligns with textbook values)
Perhaps a unit conversion problem here. At a P of 301 Bar (30.1 MPaA), rho = 46.01 kg/m^3, engineering toolbox has a good write up on this [1].

Using the correct density values in your spreadsheet, I compare the sonic output to Lenox Laser's orifice calculator [2]. To do so, I need to convert mass flow and 'standard' liters/min from [3].

standard Liter/min = mdot * 60e3 * 22.414/MW * 1000

With P0 = 200 barA and T=0 C input into both sonic calculators the outputs are within 20% of each other. This validates your sonic formulas, the primary issue is the density calculation (check your units).

Why the 20% difference?
Finally, the orifice is defined as
Cd = 0.6 (arbitrary typical number)
I estimate the ideal Cd to be 0.72 following equation 2 from [4] which is about 20% different from 0.6.

References:
[1] Helium gas Density https://www.engineeringtoolbox.com/...html?msclkid=5aa74f92ae2d11ec8afe2093b604c2d8
[2] Lenox Laser Orifice Calculator https://lenoxlaser.com/resources/ca...tor/?msclkid=69c42910ae2011ec82ce61f227854fdd
[3] Converting mass flow to sccm https://www.physicsforums.com/threa...ic-centimeters-per-minute.917608/post-6614235
[4] NIST. Comparison of CFV Theoretical Models to Experimental https://tsapps.nist.gov/publication...0961&msclkid=3570c7ddae2711ecba4468e745bee897
 
Last edited:

1. What is compressible choked gas flow?

Compressible choked gas flow refers to the flow of a gas through a restricted opening, such as an orifice, where the gas is compressed and reaches a critical flow rate known as the choked flow condition. This occurs when the gas velocity reaches the speed of sound, resulting in a constant flow rate regardless of changes in pressure.

2. How is compressible choked gas flow calculated?

The calculation for compressible choked gas flow through an orifice can be done using the Excel formula: =SQRT(((2*P1)/(gamma*R*T1))*((2/(gamma+1))^((gamma+1)/(gamma-1))-1)), where P1 is the upstream pressure, gamma is the specific heat ratio, R is the gas constant, and T1 is the upstream temperature.

3. What are the assumptions made in this Excel formula?

The Excel formula for compressible choked gas flow assumes that the gas is an ideal gas, the flow is steady and adiabatic, and there is no friction or heat transfer. It also assumes that the gas properties remain constant throughout the flow.

4. Can this Excel formula be used for all types of gases?

No, this Excel formula is specifically designed for ideal gases. It may not accurately calculate the flow of non-ideal gases, such as real gases or mixtures of gases.

5. What are the practical applications of understanding compressible choked gas flow?

Understanding compressible choked gas flow is important in various industries, such as aerospace, chemical, and oil and gas. It can be used to determine the flow rate of gases through pipes and orifices, as well as to optimize the design of gas flow systems. It is also useful in predicting the behavior of gases in high-speed flows, such as in supersonic aircraft or rocket engines.

Similar threads

  • General Engineering
Replies
10
Views
3K
Replies
3
Views
991
Replies
8
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
1
Views
3K
Replies
3
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
4
Views
2K
  • Mechanical Engineering
Replies
2
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
6
Views
5K
  • Introductory Physics Homework Help
Replies
2
Views
4K
Replies
1
Views
2K
Back
Top