Computer Graphics Question

[Invulnerability]

< Mentor Note -- thread moved to HH from the technical physics forums, so no HH Template is shown >

Problem Statement:

Derive the perspective transformation matrix in homogeneous coordinates for the case of the view plane parallel to the x-y plane and passing through z=0, when the Projection Reference Point is on the x-axis at zprp, where zprp<0.

Attempt to answer:

Anyone can help me to check whether the solution I do is correct?
Thanks

 

[Asim Riaz]

.The transformation matrix can be written as: $\begin{bmatrix} 1 & 0 & 0 & 0 \\ 0 & 1 & 0 & 0 \\ 0 & 0 & 1/z_{prp} & 0 \\ 0 & 0 & 0 & 1 \end{bmatrix}$where $z_{prp}$ is the distance of the Projection Reference Point from the origin.