- #1
WolfOfTheSteps
- 138
- 0
Homework Statement
I know how to use the method of partial fractions in most circumstances, but I'm working on a problem that has gotten the best of me. How do I get from the left side of the following identity to the right side?
[tex]
\frac{-2-2\omega^2}{-\omega^2+\sqrt{2}i\omega+1}
\ = \
\ 2 \ + \
\frac{-\sqrt{2}-2\sqrt{2}i}{i\omega -
\frac{-\sqrt{2}+i\sqrt{2}}{2}} \ + \
\frac{-\sqrt{2}-2\sqrt{2}i}{i\omega -
\frac{-\sqrt{2}-i\sqrt{2}}{2}}
[/tex]
\frac{-2-2\omega^2}{-\omega^2+\sqrt{2}i\omega+1}
\ = \
\ 2 \ + \
\frac{-\sqrt{2}-2\sqrt{2}i}{i\omega -
\frac{-\sqrt{2}+i\sqrt{2}}{2}} \ + \
\frac{-\sqrt{2}-2\sqrt{2}i}{i\omega -
\frac{-\sqrt{2}-i\sqrt{2}}{2}}
[/tex]
The Attempt at a Solution
I was able to factor the denominator and write the following equation:
[tex]
A\left(\frac{\sqrt{2}+i\sqrt{2}}{2} +i\omega\right) \ + \
B\left(\frac{\sqrt{2}-i\sqrt{2}}{2} +i\omega\right) \ = \
-2-2\omega^2
[/tex]
A\left(\frac{\sqrt{2}+i\sqrt{2}}{2} +i\omega\right) \ + \
B\left(\frac{\sqrt{2}-i\sqrt{2}}{2} +i\omega\right) \ = \
-2-2\omega^2
[/tex]
but couldn't get much further because A and B don't have [itex]\omega^2[/itex] multiples to match up with the [itex]-2\omega^2[/itex] on the right side of the equation.
How do I handle this monster?
Note: [itex]i[/itex] is the imaginary unit.
Thanks!