Continuum Mechanics Rotation Matrix Problem

In summary, the components of stress in the x_i reference Cartesian system have been determined to be 500 MPa, 700 MPa, and -100 MPa. The principal values and directions of stress have also been solved for. To determine the rotation tensor, diagonalization was used by combining the principal eigenvectors into a matrix and checking it against the diagonal matrix of the principal values. The resulting equation was found to be correct.
  • #1
lanew
13
0

Homework Statement


The components of stress in the [itex]x_i[/itex] reference Cartesian system at a point of interested have been determined to be:

[itex]
\left[\begin{array}{ccc}
500 & 0 & 300 \\
0 & 700 & 0 \\
300 & 0 & -100
\end{array}\right] \mathrm{MPa}
[/itex]

Determine the principal values and directions of stress. Determine the rotation tensor transforming the components of stress from the principal components into components along the [itex]x_i[/itex] reference Cartesian system.

Homework Equations


[itex]\mathbf{A} = \mathbf{R}^T \mathbf{V} \mathbf{R}[/itex]

where [itex]\mathbf{A}[/itex] is the original stress tensor, [itex]\mathbf{R}[/itex] is the rotation tensor, and [itex]\mathbf{V}[/itex] is a matrix of eigenvectors.

The Attempt at a Solution


I've solved for the principal values and directions, but don't know how to solve for the rotation tensor. It seems there's too many unknowns or I'm not making a necessary assumption. Does anyone have any suggestions?

Thank You.
 
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  • #2
I think I figured it out using diagonalization.

I combined the principal eigenvectors into a matrix [itex]\mathbf{R}[/itex] and checked by multiplying it by the diagonal matrix of the principal values.

[itex]\mathbf{A}=\mathbf{R}\mathbf{\lambda}\mathbf{R}[/itex]

[itex]
\left[\begin{array}{ccc}
500 & 0 & 300 \\
0 & 700 & 0 \\
300 & 0 & -100
\end{array}\right] =
\left[\begin{array}{ccc}
V_1 & V_2 & V_3 \\
V_1 & V_2 & V_3 \\
V_1 & V_2 & V_3
\end{array}\right]
\left[\begin{array}{ccc}
\lambda_1 & 0 & 0 \\
0 & \lambda_2 & 0 \\
0 & 0 & \lambda_3
\end{array}\right]
\left[\begin{array}{ccc}
V_1 & V_1 & V_1 \\
V_2 & V_2 & V_2 \\
V_3 & V_3 & V_3
\end{array}\right]
[/itex]

When I evaluated the right side, it equated to the left.

Does this seem correct?

Thanks Again.
 
Last edited:

What is the rotation matrix in continuum mechanics?

In continuum mechanics, the rotation matrix is a mathematical tool that describes the orientation of a body or object in three-dimensional space. It is a 3x3 matrix that represents the transformation of coordinates between two coordinate systems that are rotated with respect to each other.

How is the rotation matrix used in continuum mechanics?

The rotation matrix is used in continuum mechanics to analyze the deformation and motion of objects and materials. It helps to describe the change in shape and orientation of a body under different conditions, such as applied forces or thermal loading. It is also used to calculate stress and strain tensors, which are important measures of the mechanical behavior of materials.

What is the significance of the rotation matrix in continuum mechanics?

The rotation matrix is significant in continuum mechanics because it allows for the accurate representation of the complex 3D deformations and rotations that occur in real-world engineering and scientific applications. It is a fundamental tool in analyzing and understanding the behavior of materials and structures under different loading conditions.

How is the rotation matrix calculated in continuum mechanics?

The rotation matrix is calculated using mathematical principles, such as linear algebra and vector calculus. It can be derived from the transformation of coordinates between two coordinate systems, using rotation matrices and transformation matrices. Alternatively, it can also be calculated by using the rotation angle and the axis of rotation.

Can the rotation matrix be used for non-linear deformations in continuum mechanics?

Yes, the rotation matrix can be used for both linear and non-linear deformations in continuum mechanics. However, in non-linear situations, the rotation matrix may vary with position and time, making the analysis more complex. In some cases, it may be necessary to use a different rotation matrix for each point in a deformable body.

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