- #1
koochiee
- 16
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Is it possible for a Type 0 Open Loop Transfer function to have 0 steady state error?
Context - Control System Gain design to meet a certain steady state error specification.
The open loop T.F - G(s)=3/(s^2 +4s+3) (This is type 0 (n=0))
The closed loop T.F is Gc(s)=G(s)/(1+KG(s)), But my problem is will changing the value of K or adding gain would make a difference? Because the Open loop T.F. is Type 0, the steady state error for 1. step i/p - constant
2. ramp & parabolic i/p - infinity, Any help is much appreciated. :)
Context - Control System Gain design to meet a certain steady state error specification.
The open loop T.F - G(s)=3/(s^2 +4s+3) (This is type 0 (n=0))
The closed loop T.F is Gc(s)=G(s)/(1+KG(s)), But my problem is will changing the value of K or adding gain would make a difference? Because the Open loop T.F. is Type 0, the steady state error for 1. step i/p - constant
2. ramp & parabolic i/p - infinity, Any help is much appreciated. :)
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