- #1
1question
- 67
- 0
Homework Statement
Hi. I have convert the following equation (which is in ionic form) into neutral form:
4S2O32-+O2+2H2O=2S4O62-+4OH-
The question tells me to use calcium as a counterion for all anions.
Homework Equations
N/A
The Attempt at a Solution
I basically just added calcium to the anions above, resulting in:
4CaS2O3+O2+2H2O=2CaS4O6+4Ca(OH)2
Unfortunately, when I do a check, the coefficients of each element/compound do not match. Trying to balance it doesn't work.