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Ben Brain
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How are Cooper pairs being in the same quantum state responsible for superconductivity? Why does them being in the same quantum state matter? Please no complex mathematics, I don't understand that stuff :)
phyzguy said:A simple answer is that electrons, being spin-1/2, are fermions and obey the Pauli exclusion principle. So that no two of them can be in the same quantum state. When the electrons pair up, the pair has spin-1.
Thanks for the clarification. So @Ben Brain, ZapperZ is saying that I should have said, "When the electrons pair up, the pair has spin-0". Spin-0 is still even spin, so still a boson, so everything else I said still applies.ZapperZ said:Just be aware that triplet-spin state superconductors are rather rare. Most of the superconductors are singlet-spin state, i.e. total spin of 0.
Zz.
Cooper pairs are a phenomenon in superconductivity where two electrons with opposite spin are bound together and behave as a single particle. This pairing occurs due to the interaction between electrons and the surrounding lattice vibrations.
The formation of Cooper pairs allows for the electrons to move through the material without resistance, resulting in zero electrical resistance and perfect conductivity. This is known as the BCS theory of superconductivity.
Conventional superconductors follow the BCS theory and have a clear understanding of Cooper pairs and their role in superconductivity. Unconventional superconductors do not follow the BCS theory and have other mechanisms for achieving superconductivity.
The Meissner effect is a phenomenon where a superconductor expels all magnetic fields from its interior when it becomes superconducting. This effect is a result of the formation of Cooper pairs and their ability to carry current without resistance.
No, Cooper pairs require low temperatures to form and exist. At high temperatures, thermal energy breaks up the pairs and the material loses its superconducting properties.