- #1
horsedeg
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Homework Statement
A uniformly charged insulating rod of length 10.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod has a total charge of -9.00 µC. Find the electric potential at O, the center of the semicircle.
Homework Equations
V=keQ/r
The Attempt at a Solution
I already found the answer. It is as simple as plugging in the radius and charge into the relevant equation I wrote. However, why? I don't really understand. At first I was thinking that I have to find the electric field or something and integrate using that one formula, but why is it this simple? Is direction completely irrelevant?