Determine the signs of ∆H, ∆G, ∆S for the reaction: N2(g) → 2N(g)

Thread starter aquastor
Start date Apr 10, 2023
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Reaction Thermodaynamics

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Apr 10, 2023

aquastor

Homework Statement: Determine the signs of ∆H, ∆G, ∆S for the reaction: N2(g) → 2N(g) Assume standard conditions and temperature = 25 oC

Relevant Equations: ∆G=∆H-T∆S

Hello are you able to explain the two incorrect ones. I am not sure how to do this as there is no phase change involved, nor is there a temperature or volume change.

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Apr 12, 2023

DrClaude

Mentor

Which form of nitrogen do you find in nature? What does that tell you about the ΔG of the given reaction?

1. What is the meaning of ∆H, ∆G, and ∆S in this reaction?

∆H, ∆G, and ∆S are thermodynamic parameters that describe the energy changes in a reaction. ∆H represents the change in enthalpy, ∆G represents the change in Gibbs free energy, and ∆S represents the change in entropy.

2. How can the signs of ∆H, ∆G, and ∆S be determined for this reaction?

The signs of ∆H, ∆G, and ∆S can be determined by comparing the energy levels of the reactants and products. If the energy level of the products is lower than the energy level of the reactants, ∆H will be negative, ∆G will be negative, and ∆S will be positive. If the energy level of the products is higher than the energy level of the reactants, ∆H will be positive, ∆G will be positive, and ∆S will be negative.

3. What does a negative value for ∆H indicate?

A negative value for ∆H indicates that the reaction is exothermic, meaning that it releases heat to the surroundings. This indicates that the bonds in the products are stronger than the bonds in the reactants, resulting in a decrease in energy.

4. How does the sign of ∆G determine the spontaneity of the reaction?

The sign of ∆G determines the spontaneity of the reaction. A negative value for ∆G indicates that the reaction is spontaneous, meaning that it will occur without the input of external energy. A positive value for ∆G indicates that the reaction is non-spontaneous and will not occur without the input of external energy.

5. What is the significance of the sign of ∆S in this reaction?

The sign of ∆S indicates the change in disorder or randomness of the system. A positive value for ∆S indicates an increase in disorder, while a negative value for ∆S indicates a decrease in disorder. In this reaction, a positive value for ∆S means that the products have a higher degree of disorder than the reactants.