- #1
Johnstonator
- 5
- 0
- Homework Statement
- What value of alpha is required to make this a valid interconnection?
For this value of alpha, find the power associated with the current source.
- Relevant Equations
- v= alpha * i
P= i v
So I'm confused on a few things about this circuit. I know my math is right (since I got the absolute values correct), but the signs are off since I can't tell when the voltage, current or if the general power equation is positive or negative.
A) So my first question is, where is the current going? Is it going CW like what I drew in on here (based off of the current source) or is it going the opposite direction because of iDelta? My confusion stems from the other two questions below
B) The current iDelta in the first equation should be negative 15mA because it's pointed opposite from the current source right?
C) Is the voltage negative (-6V in the first equation)? The dependent voltage source polarity is different than the 6V polarity so I guess I can see that but is that something I'll have to remember rather than understand?
D) Finally, is the general power equation (P = i v) negative or positive? Since positive current entering a positive terminal is positive power, and in this case the current (dictated by iDelta) enters a negative terminal, I want to say it's negative. But if I use P = - i v, and current is negative, and voltage is negative, my power is negative (when the power is really positive).
A) So my first question is, where is the current going? Is it going CW like what I drew in on here (based off of the current source) or is it going the opposite direction because of iDelta? My confusion stems from the other two questions below
B) The current iDelta in the first equation should be negative 15mA because it's pointed opposite from the current source right?
C) Is the voltage negative (-6V in the first equation)? The dependent voltage source polarity is different than the 6V polarity so I guess I can see that but is that something I'll have to remember rather than understand?
D) Finally, is the general power equation (P = i v) negative or positive? Since positive current entering a positive terminal is positive power, and in this case the current (dictated by iDelta) enters a negative terminal, I want to say it's negative. But if I use P = - i v, and current is negative, and voltage is negative, my power is negative (when the power is really positive).