Different situations demand different forces having different directions. Some people think that the force is directed along the rod in such problems. That is not necessarily correct. The recipe is to find the vertical and horizontal components and get the direction from these. This is a static equilibrium problem therefore, the sum of all the forces and torques must be zero.bolzano95 said:
Not wrong, exactly, but image 2 is certainly misleading. The force F at the joint is shown as horizontal, but since no angles are given explicitly you should not trust that. Indeed, if you take moments about the other end of the rod then only F and mg have any torque, and both seem to be anticlockwise.bolzano95 said:
The direction of the force exerted by a wall on a rod is perpendicular to the surface of the wall. In other words, it is directed away from the wall and towards the rod.
Yes, the direction of the force exerted by the wall on the rod will change if the rod is angled. The force will still be perpendicular to the surface of the wall, but it will be at an angle to the rod's orientation.
The direction of the force can be determined by drawing a free-body diagram of the rod and analyzing the forces acting on it. The force exerted by the wall will be represented by an arrow pointing away from the wall and towards the rod.
No, the direction of the force exerted by the wall on the rod can change depending on the orientation and position of the rod in relation to the wall. It will always be perpendicular to the surface of the wall, but the angle at which it is exerted may vary.
The direction of the force exerted by the wall is an important factor in determining the stability of the rod. If the force is directed towards the center of mass of the rod, it will help keep the rod in place and maintain its stability. However, if the force is directed away from the center of mass, it may cause the rod to become unbalanced and potentially fall over.
