Does an object slow down when it enters water?

  • Thread starter Nishantkumar19
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    Buoyancy
In summary, when a dense object sinks in water, it sinks at a constant rate, because the buoyancy and fluid drag counteract the weight of the object.
  • #1
Nishantkumar19
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When a dense object sinks in water, it sinks at a constant rate, because the buoyancy and fluid drag counteract the weight of the object.

But if there is no resultant force, then why does the object slow down when it enters the water? Eg. if it's traveling at 2 m/s when it enters the water, shouldn't it continue to travel at 2m/s inside the water, because the forces are balanced?

Is there some kind of force that slows down the object WHILE it's entering the water, but doesn't do anything once the object is fully in the water?
 
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  • #2
Nishantkumar19 said:
When a dense object sinks in water, it sinks at a constant rate, because the buoyancy and fluid drag counteract the weight of the object.
Why would you expect buoyancy and drag to be exactly equal to the weight of the dense object?
 
  • #3
Hint: Drag is a function of speed.
 
  • #4
Okay so we did this experiment in school, and we dropped a steel ball into glycerin. After entering the water, it slowly sank at a constant speed, so that's how I know that the drag and buoyancy are equal to the weight.

Does drag increase with speed? Is it directly proportional or something?
That means the drag would initially be greater than the weight, but as the speed reduced, the drag would reduce until it's equal to the weight, and then the object would sink at constant speed. Also, is the buoyancy force stronger than the drag? Or is it the drag that mostly counteracts the weight?
 
  • #5
Nishantkumar19 said:
Does drag increase with speed? Is it directly proportional or something?
It is not always as simple as a direct proportion. But yes, drag increases with speed.
That means the drag would initially be greater than the weight, but as the speed reduced, the drag would reduce until it's equal to the weight, and then the object would sink at constant speed.
Bingo. The reverse happens as well. If an object is gently released then drag is initially zero and increases until the object sinks at constant speed. Google "terminal velocity".
Also, is the buoyancy force stronger than the drag? Or is it the drag that mostly counteracts the weight?
It depends on the situation. For a piece of waterlogged wood that is just barely more dense than water, buoyancy will be dominant and drag will be relatively small. For a lump of lead that is much more dense than water, drag will be dominant and buoyancy will be relatively small. For a ping pong ball flung into the water at high speed, drag will dominate -- briefly.
 
  • #6
Okay got it. Thanks
 

What is buoyancy?

Buoyancy is the upward force exerted by a fluid, such as water, on an object that is immersed in it. This force is caused by the difference in pressure between the top and bottom of the object.

How does an object sink or float?

An object will sink if its weight is greater than the buoyant force acting on it. On the other hand, if the buoyant force is greater than the object's weight, it will float. This is why objects made of denser materials, such as lead, will sink while objects made of less dense materials, like wood, will float.

What factors affect buoyancy?

The main factors that affect buoyancy are the density of the fluid and the volume and shape of the object. A more dense fluid will exert a greater upward force, while a larger or more buoyant object will experience a greater upward force.

Why do some objects sink and others float?

Objects sink or float depending on their density compared to the density of the fluid they are in. If an object is less dense than the fluid, it will float because the buoyant force will be greater than its weight. If it is more dense, it will sink because its weight is greater than the buoyant force.

How is the buoyant force calculated?

The buoyant force is equal to the weight of the fluid that is displaced by the object. This can be calculated using Archimedes' principle, which states that the buoyant force is equal to the weight of the fluid displaced by an object. The formula for calculating the buoyant force is Fb = ρVg, where ρ is the density of the fluid, V is the volume of the displaced fluid, and g is the acceleration due to gravity.

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