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Snow blower Stanley SS30
Type :Dual Stage
Maximum RPM: 3600
Torque : 21.56 Nm
Impeller Diameter :16" inch
Auger Diameter:16" inch
CC: 302
Tire Size : 16" * 6.5
I do not know the gear ratio : if assume its 12:1
Gear output torque will be 258.72 Nm
Assume the Shaft diameter = 44 mm=0.044m
shear force=(pi *d^2/2)∗ shear strength of the material ( for double shear)
shear force = (pi * 12^2/2)∗186
shear force = 42072 N
M = shear force * L
M= 42072* 0.044
M = 1851.168 Nm
why i am getting so value for the shear pin because the maximum output torque is just 258.72 so the shear pin should break before this value isn't it?
Assume the Shaft diameter = 44 mm=0.044m
shear force=(pi *d^2/2)∗ shear strength of the material ( for double shear)
shear force = (pi * 12^2/2)∗186
shear force = 42072 N
M = shear force * L
M= 42072* 0.044
M = 1851.168 Nm
why i am getting so value for the shear pin because the maximum output torque is just 258.72 so the shear pin should break before this value isn't it?
Type :Dual Stage
Maximum RPM: 3600
Torque : 21.56 Nm
Impeller Diameter :16" inch
Auger Diameter:16" inch
CC: 302
Tire Size : 16" * 6.5
I do not know the gear ratio : if assume its 12:1
Gear output torque will be 258.72 Nm
Homework Equations
Assume the Shaft diameter = 44 mm=0.044m
shear force=(pi *d^2/2)∗ shear strength of the material ( for double shear)
shear force = (pi * 12^2/2)∗186
shear force = 42072 N
M = shear force * L
M= 42072* 0.044
M = 1851.168 Nm
why i am getting so value for the shear pin because the maximum output torque is just 258.72 so the shear pin should break before this value isn't it?
The Attempt at a Solution
Assume the Shaft diameter = 44 mm=0.044m
shear force=(pi *d^2/2)∗ shear strength of the material ( for double shear)
shear force = (pi * 12^2/2)∗186
shear force = 42072 N
M = shear force * L
M= 42072* 0.044
M = 1851.168 Nm
why i am getting so value for the shear pin because the maximum output torque is just 258.72 so the shear pin should break before this value isn't it?
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