- #1
tristanm
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Homework Statement
Two point charges (q1 = -2.6uC and q2 = 8.6uC) are fixed along the x-axis, separated by a distance d = 9.7cm. Point P is located at (x,y) = (d,d)
1. What is Ex(P), the x-component of the electric field produced by q1 and q2 at point P?
2. What is Ey(P), the value of the y-component of the electric field produced by q1 and q2 at point P?
3.A third charge is now positioned along the y-axis at distant d from and above q1 on (x,y) = (0,d). What is the Ex(P) of the field produced by all 3 charges at point P?
4. Suppose all are doubled, how will the electric field change?
5. How would you change Q1 in order to make the eletric field at point P equal to zero?
Homework Equations
E = (kq)/r^2
Exq1 = ((kq)/r^2)cos(45)
Exq2 = 0
Eyq1 = ((kq/r^2)sin(45)
Eyq2 = (kq)/r^2
C^2 = A^2 + B^2
Image for 1 and 2
Image for 3, 4, and 5
The Attempt at a Solution
1. First off, I drew the triangle of q1-q2-P and labelled all d values as 0.097m, used E=(kq)/r^2 to find the magnitude of E at point P a distance r = sqrt(2d^2) and then multiply that value by cos(45) to find that Exq1 is equal to -120608.8429 N/C by having q = 2.6e-6 C, k = 8.987551e9 and r = (which apparently is wrong)
2. Ey = Eyq1 + Eyq2, where Eyq1 = ((kq1)/r^2) * sin45 and Eyq2 = (kq2)/d^2. For Eyq1 I calculated -120451.7144 N/C and for Eyq2 I calculated 8214787.82 N/C. The sum of the two is 8094336.106 N/C which again, is apparently wrong.
I have not yet attempted 3,4 or 5 because I recognize after the first two I'm clearly doing something wrong in my steps.