How Much Voltage Is Needed to Suspend Charged Water Droplets?

In summary, the electric field between two charged plates is inversely proportional to the distance between them. This is why you need to supply a higher voltage to keep the droplets hovering in the air.
  • #1
Chawker
2
0

Homework Statement


You intend to suspend water droplets in mid-air to understand rainfall.

You give the droplets a small positive charge, and keep them suspended by an electric field upwards.

The experiment consists of two horizontal metal plates, separated by 9.3m. The water droplets have a mass of 2.8 * 10^-9 kg and have a charge of 6.4*10^-10 C

What voltage should you supply to keep them hovering?

Homework Equations



V = E/d
E=kq/r^2[/B]

The Attempt at a Solution



Kind of lost on this one. I thought about using e=kq/r^2 with the given information then substituting it into the first equation however that still doesn't include the mass component of the question, even if its needed at all.

How should i go about this problem?
 
Last edited:
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  • #2
Hello Chawker, :welcome:

Chawker said:
V = e/d
In turn, I am lost on this one. You could have avoided that by listing your variable names in part 1 (e = electric field strength ? In physics e is electron charge) Then your eqn doesn't fly dimensonally at all. Where does it come from ?

Chawker said:
seperated by 9.3m
big experiment ?

Your elevant equations set is incomplete: they do not feature the mass at all.
 
  • #3
For drops to hover the Electric force ##F = Eq ## must balance the gravitational force ## F=mg ##. What is the E field?

Edit: ##E = \frac{Kq}{r^2} ## is for point charges. What kind of Electric field is there between two charged plates ?
 
  • #4
Chawker said:
two horizontal metal plates
form a capacitor
 
  • #5
PumpkinCougar95 said:
For drops to hover the Electric force ##F = Eq ## must balance the gravitational force ## F=mg ##. What is the E field?

Edit: ##E = \frac{Kq}{r^2} ## is for point charges. What kind of Electric field is there between two charged plates ?

So we're looking at Eq = mg then solving v = E *d?

EDIT : Figured it out, thanks for the help guys!
 
  • #6
You're welcome
 

1. What is an electric field?

An electric field is a physical field that is created by electrically charged particles. It is a property of space that describes the influence that a charged object has on other charged objects in its vicinity.

2. How is an electric field calculated?

The electric field is calculated by dividing the force exerted on a charged particle by the magnitude of the charge. It is measured in units of Newtons per Coulomb (N/C).

3. What is the difference between an electric field and an electric potential?

An electric field is a physical field that describes the force exerted on a charged particle, while electric potential is a measure of the potential energy per unit charge at a given point in space. In other words, electric potential describes the strength of an electric field at a specific point.

4. How does an electric field affect charged particles?

An electric field exerts a force on charged particles, causing them to move in a certain direction. The direction of the force depends on the charge of the particle and the direction of the electric field. Positively charged particles will be pushed in the direction of the electric field, while negatively charged particles will be pushed in the opposite direction.

5. What are some real-world applications of electric fields?

Electric fields have many practical applications, such as in electronics, where they are used to control the flow of electricity in circuits. They are also used in electrostatic precipitators to remove pollutants from the air, and in particle accelerators to accelerate charged particles to high speeds. Electric fields are also essential in the function of many biological processes, such as nerve impulses in the human body.

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