I edited it to put the whole original problem. thanksDelta2 said:
What do you mean? s is radial component in cylindricalharuspex said:
So what is the distance from (s, Φ, z) to (0, 0, h)?jkthejetplane said:
I believe that's my main question above if i am understanding you correctly. I am not sure how to define the separation vector. Right not i have it as (h-z)zhat + (r-s)shat but i am unsure on the s direction component...haruspex said:
By symmetry, Φ doesn't matter, so it reduces to Cartesian: (s, z) to (0, h).jkthejetplane said:
The formula for calculating the electric potential of a point outside a cylinder is V = kQ/r, where V is the electric potential, k is the Coulomb's constant, Q is the charge of the cylinder, and r is the distance from the point to the center of the cylinder.
The electric potential decreases as the distance from the cylinder increases. This is because the electric field strength decreases with distance, and the electric potential is directly proportional to the electric field strength.
Yes, the electric potential of a point outside a cylinder can be negative if the charge of the cylinder is negative. This means that the electric potential energy of a positive charge placed at that point would decrease, indicating a negative potential.
The radius of the cylinder has a direct effect on the electric potential at a point outside the cylinder. As the radius increases, the electric potential decreases, and vice versa. This is because a larger radius means a larger distance from the center of the cylinder, resulting in a weaker electric field.
Yes, the electric potential of a point outside a cylinder can be zero if the charge of the cylinder is zero or if the point is located on the axis of the cylinder. This means that the electric potential energy of a charge placed at that point would be zero, indicating no potential difference.
