Electronic Circuit with 2 diodes

In summary: Not really sure how to answer the load attached question, this is all I know about the problem. I believe there is load.I forgot to mention that it is also possible that some state are impossible.
  • #1
masterchiefo
212
2

Homework Statement


dNAX4as.png


I have to find Vo in every diode state possible.
We know diode Vf = 0.7

Homework Equations


Va-Vc < 0.7 = diode OFF
Va-VC > 0.7 = diode ON

The Attempt at a Solution


State 1:
if D1 OFF and D2 OFF
Vo will be equal to Vi

State 2:
if D1 OFF and D2 ON
Vo will be equal to Vi

State 3:
if D1 ON and D2 OFF
Vo will be equal to 0.7 since the diode is limiting component it at 0.7

State 4:
if D1 ON and D2 ON
Vo= impossible since D2 will not receive enough volt to activate, it will receive less than 0.7 as the resistance will take some.
 
Physics news on Phys.org
  • #2
masterchiefo said:

Homework Statement


View attachment 204809

I have to find Vo in every diode state possible.
We know diode Vf = 0.7

Homework Equations


Va-Vc < 0.7 = diode OFF
Va-VC > 0.7 = diode ON

The Attempt at a Solution


State 1:
if D1 OFF and D2 OFF
Vo will be equal to Vi

State 2:
if D1 OFF and D2 ON
Vo will be equal to Vi

State 3:
if D1 ON and D2 OFF
Vo will be equal to 0.7 since the diode is limiting component it at 0.7

State 4:
if D1 ON and D2 ON
Vo= impossible since D2 will not receive enough volt to activate, it will receive less than 0.7 as the resistance will take some.
What is your question?

To what extent are the diodes to be considered to be ideal ?
 
  • #3
masterchiefo said:
if D1 OFF and D2 OFF
Vo will be equal to Vi
Only if there is no load (see state 3).
masterchiefo said:
if D1 OFF and D2 ON
Vo will be equal to Vi
Why?
masterchiefo said:
if D1 ON and D2 OFF
Vo will be equal to 0.7 since the diode is limiting component it at 0.7
I don't understand that argument, and the conclusion is wrong. This state is only possible if there is a load at V0.
masterchiefo said:
if D1 ON and D2 ON
Vo= impossible since D2 will not receive enough volt to activate, it will receive less than 0.7 as the resistance will take some.
I don't understand that argument and the conclusion is wrong.
 
  • #4
mfb said:
Only if there is no load (see state 3).
Why?I don't understand that argument, and the conclusion is wrong. This state is only possible if there is a load at V0.I don't understand that argument and the conclusion is wrong.

Each state is independent from each other, its like 4 different problems.
In state 1, both are off so its like there is no diode at all and the second resistor is out as well.
which means Vo = Vi

for state 2, I honestly have no idea how to do it. It confuse me a lot. Can you give me some tips ?

For state 3, I came up with a different solution : Vo = Vi - 0.7

For state 4, I came up with the same solution as state 3, Vi -0.7 = Vo
 
  • #5
SammyS said:
What is your question?

To what extent are the diodes to be considered to be ideal ?
They are perfectly ideal, with vf = 0.7
question is to find Vo in every state as stated in the first post.

Each state is an independent problem.
 
  • #6
masterchiefo said:
In state 1, both are off so its like there is no diode at all and the second resistor is out as well.
Only if there is no load at V0. But if there is no load, you never have current through D1!
masterchiefo said:
for state 2, I honestly have no idea how to do it. It confuse me a lot. Can you give me some tips ?
If diode 2 is conducting current, where does the current go? What does that mean for the voltages? There are two things you can say.
masterchiefo said:
For state 3, I came up with a different solution : Vo = Vi - 0.7
Only with a load. Otherwise: Where does the current go?
masterchiefo said:
For state 4, I came up with the same solution as state 3, Vi -0.7 = Vo
Again, that needs a load, and the way you answer state 1 there is no load.
You can make an additional statement in this case, based on the conducting diode 2.Can you have a load attached yes or no?
 
  • #7
mfb said:
Only if there is no load at V0. But if there is no load, you never have current through D1!If diode 2 is conducting current, where does the current go? What does that mean for the voltages? There are two things you can say.
Only with a load. Otherwise: Where does the current go?
Again, that needs a load, and the way you answer state 1 there is no load.
You can make an additional statement in this case, based on the conducting diode 2.Can you have a load attached yes or no?
Not really sure how to answer the load attached question, this is all I know about the problem. I believe there is load.
I forgot to mention that it is also possible that some state are impossible.

For state 1, that would mean Vo = R*I

For state 2, I would say current would go to Vo, as D1 can't receive current in that direction. only from Anode to cathode.
so Vo would be -0.7 - R*I = Vo

I want to clear state 1 and 2 before trying again with 3 and 4, one step at a time so I understand the problem correctly
 
  • #8
Okay, with possible loads then.
masterchiefo said:
For state 1, that would mean Vo = R*I
That is the voltage drop at the resistor, the difference between two potentials - it is not Vi or V0
masterchiefo said:
For state 2, I would say current would go to Vo, as D1 can't receive current in that direction.
But the resistor can.
masterchiefo said:
so Vo would be -0.7 - R*I = Vo
Right, assuming I is the current flowing through the lower part.
 
  • #9
masterchiefo said:
.
Staes 1, 3, 4 OK
State 2 wrong.
 

1. What is an electronic circuit with 2 diodes?

An electronic circuit with 2 diodes is a type of circuit that contains two diodes, which are electronic components that allow current to flow in only one direction. These circuits are often used in electronic devices to control the flow of electricity and can have various applications.

2. How does a circuit with 2 diodes work?

In a circuit with 2 diodes, one diode acts as a rectifier, allowing current to flow in one direction, while the other diode acts as a regulator, controlling the voltage level. This allows the circuit to convert AC (alternating current) to DC (direct current) and regulate the voltage to a specific level.

3. What are the advantages of using a circuit with 2 diodes?

Circuits with 2 diodes have several advantages, including their ability to convert AC to DC, regulate voltage, and protect other components from overvoltage. They are also relatively simple and cost-effective compared to other types of circuits.

4. What are some common applications of circuits with 2 diodes?

Circuits with 2 diodes are commonly used in power supplies for electronic devices, such as computers, televisions, and smartphones. They are also used in battery chargers, voltage regulators, and audio amplifiers.

5. Can circuits with 2 diodes be used in other types of circuits?

Yes, circuits with 2 diodes can be used in various types of circuits, including rectifier circuits, voltage regulator circuits, and signal processing circuits. They can also be combined with other components to create more complex circuits for specific applications.

Similar threads

  • Introductory Physics Homework Help
Replies
26
Views
3K
  • Engineering and Comp Sci Homework Help
Replies
19
Views
4K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
9
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
4
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
7
Views
3K
  • Engineering and Comp Sci Homework Help
Replies
2
Views
5K
  • Engineering and Comp Sci Homework Help
Replies
9
Views
1K
  • Introductory Physics Homework Help
Replies
9
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
9
Views
5K
Back
Top