- #1
harpazo
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Evaluate ∫∫∫ over E, where E is the solid enclosed by the ellipsoid
x^2/a^2 + y^2/b^2 + z^2/c^2 = 1.
Use the transformation x = au,
y = bv, z = cw.
I decided to replace x with au, y with bv and z with cw in the ellipsoid.
After simplifying, I got
u^2 + v^2 + w^2 = 1.
What is the next step?
The answer is (4/3)πabc.
What is the correct set up leading to the answer?
A friend responded to my email by saying this:
You Are asked to evaluate ∫∫∫ dV over the domain E. dV = dx dy dz. From your change of variables, we get that dx = a du, dy = b dv & dz = c dw. Replacing makes dV = abc du dv dw. Factoring out abc gives
abc ∫∫∫ du dv dw over the domain u^2 + v^2 + w^2 = 1. But that integral is nothing more than the volume of a sphere of radius 1, which you [should] know by heart. Your answer then follows.
Question:
WHAT ARE THE BOUNDS?
x^2/a^2 + y^2/b^2 + z^2/c^2 = 1.
Use the transformation x = au,
y = bv, z = cw.
I decided to replace x with au, y with bv and z with cw in the ellipsoid.
After simplifying, I got
u^2 + v^2 + w^2 = 1.
What is the next step?
The answer is (4/3)πabc.
What is the correct set up leading to the answer?
A friend responded to my email by saying this:
You Are asked to evaluate ∫∫∫ dV over the domain E. dV = dx dy dz. From your change of variables, we get that dx = a du, dy = b dv & dz = c dw. Replacing makes dV = abc du dv dw. Factoring out abc gives
abc ∫∫∫ du dv dw over the domain u^2 + v^2 + w^2 = 1. But that integral is nothing more than the volume of a sphere of radius 1, which you [should] know by heart. Your answer then follows.
Question:
WHAT ARE THE BOUNDS?
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