- #1
yxgao
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Hi,
I'm trying to evaluate the following integral to calculate the scattering cross section for a spherically symmetrical potential [tex]e^{\frac{-r^2}{a^2}}[/tex]?
[tex]f(\theta)=\int r e^{\frac{-r^2}{a^2}} sin(kr) dr[/tex] where a is a constant.
What is the easiest way to evaluate this? I was able to get the answer by doing the integral using Mathematica but I don't know how to do this by hand.
Also, is the approximation better for low energies or high energies??
Thanks!
I'm trying to evaluate the following integral to calculate the scattering cross section for a spherically symmetrical potential [tex]e^{\frac{-r^2}{a^2}}[/tex]?
[tex]f(\theta)=\int r e^{\frac{-r^2}{a^2}} sin(kr) dr[/tex] where a is a constant.
What is the easiest way to evaluate this? I was able to get the answer by doing the integral using Mathematica but I don't know how to do this by hand.
Also, is the approximation better for low energies or high energies??
Thanks!
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