- #1
jk22
- 729
- 24
I consider the Dirac delta.
In physics the delta squared has an infinite norm : $$\int\delta (x)^2=\infty $$
But if i look at delta being a functional i could write : $$\delta [f]=f (0) $$ hence $$\delta^2 [f]=\delta [\delta [f]]=\delta [\underbrace {f (0)}_{constant function}]=f (0)$$
Thus in this view $$\delta^2=\delta $$ ?
In physics the delta squared has an infinite norm : $$\int\delta (x)^2=\infty $$
But if i look at delta being a functional i could write : $$\delta [f]=f (0) $$ hence $$\delta^2 [f]=\delta [\delta [f]]=\delta [\underbrace {f (0)}_{constant function}]=f (0)$$
Thus in this view $$\delta^2=\delta $$ ?