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vvvivvvian
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Homework Statement
A(n) 895 N crate is being pushed across a level floor by a force of 397 N at an angle of 21◦ above the horizontal. The coefficient of kinetic friction between the crate and the floor is 0.24. The acceleration of gravity is 9.81 m/s.
What is the acceleration of the box? Answer in units of m/s/s
The Attempt at a Solution
to find mass, Fg = mg
895 = m9.8
m = 91.3265I've tried
ΣFy = FN - mg - FAsinθ
ΣFy = FN - mg - FAsinθ = ma
ΣFy = FN - mg - FAsinθ = 0
FN = mg + 397sin21
FN = 895 + 142.272
FN = 1037.27
∑Fx = FAcosθ - Ff
∑Fx = 397cos21 - (0.24)(1037.27)
397cos21 - (0.24)(1037.27) = ma
397cos21 - (0.24)(1037.27) = (91.3265)a
= 1.33 m/s/s but this is not correct
can anyone tell me where i went wrong/what is the correct way? thanks