Find equivalent resistance R in the circuit

In summary: It can help simplify more complex circuits. Just be careful with the algebra and make sure to include the delta-wye transformation in your final answer. In summary, the discussion covers the concept of parallel resistors and how they must be directly connected to each other with no intervening resistance. The use of various circuit analysis methods is also mentioned, including Kirchhoff's laws and delta-wye transformations. The conversation also offers a helpful resource for further understanding. Ultimately, the delta-wye transformation method is recommended for solving the given problem due to its ability to simplify complex circuits.
  • #1
valhakla
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Homework Statement
Help me to find the total resistance between two points A and B. I have tried to find the total resistance using the formulas Rparralel1 = 2R * 2R /2R+2R, Rparallel2 = 6R *3R / 6R + 3R, and R total = Rparralel1 + Rparralel2 + 2R, the answer was incorrect. Can you tell me where is my mistake, and how can I determine parallel and series resistors to find the total resistance in such circuits?
Relevant Equations
R_parallel = R1 * R2 / R1 + R2, R_series = R1 + R2
Screenshot 2023-05-31 at 17.59.50.png
 
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  • #2
valhakla said:
Rparralel1 = 2R * 2R /2R+2R,
The two R2 on the left are not parallel. To count as parallel, the two resistors must be directly connected to each other, with no intervening resistance, at each end.
 
  • #3
I should add to what @haruspex noted that if two resistors are not parallel, this does not mean that they must be in series. It is entirely possible to have circuits where there are no parallel or series combinations.
 
  • #4
@valhakla What circuit analysis methods have you learned? Have you covered KCL, KVL? How about mesh and nodal analysis? Perhaps delta-Y and y-delta transforms?
 
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  • #5
gneill said:
@valhakla What circuit analysis methods have you learned? Have you covered KCL, KVL? How about mesh and nodal analysis? Perhaps delta-Y and y-delta transforms
Yes, I have tried to apply Kirchkhoff's and loop rule for this ciruit, but it didn't helped, as it gives only the values of the current flowing through particular resistor not the total resistance between points A and B. Regarding the transforms, I am not familiar with that yet.
 
  • #6
haruspex said:
The two R2 on the left are not parallel. To count as parallel, the two resistors must be directly connected to each other, with no intervening resistance, at each end.
I understood. So are there any algorithms to approach such circuits? This is my first time encountering this.
 
  • #8
valhakla said:
Yes, I have tried to apply Kirchkhoff's and loop rule for this ciruit
That’s enough to solve the problem. If that’s all you have covered in class so far, I’d guess that’s what you are meant to use.

Add a battery (emf ##= E##) between A and B so you have a complete circuit.

Analyse the circuit using Kirchhoff’s first law (the ‘current rule’) and second law (the ‘loop rule’). You can find the total current, ##I##, entering A (or leaving B) in terms of ##E## and ##R##.

The resistance between A and B is then ##\frac EI##. ##E## should cancel and the answer will be some multiple of ##R##.

It’s messy because you have a lot of unknown currents.

Note the circuit is ‘linear’. Without loss of generality, you can consider the case with ##R=1 \Omega## and take the battery’s emf as some convenient arbitrary value (e.g. ##E =10V##). The final answer will be a multiple of ##R##, not ohms. However, if you are not comfortable with this ‘shortcut’ you will need to work with the symbols ##R## and ##E##.

Post your working if you need further help.

Also, note spelling: Kirchhoff.
 
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  • #10
Steve4Physics said:
Add a battery (emf ##= E##) between A and B so you have a complete circuit.
I tried to add 10V battery, but my final answer wasn't even close. However the delta-wye transformation method helped me to finally solve the problem.
 
  • #11
valhakla said:
I tried to add 10V battery, but my final answer wasn't even close.
The risk of algebra/arithmetic errors is high with 5 unknowns! But it will work.

valhakla said:
However the delta-wye transformation method helped me to finally solve the problem.
It's a good choice if you are allowed to use that method.
 
  • Informative
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1. What is equivalent resistance?

Equivalent resistance is the single resistance value that can replace a complex network of resistors and produce the same overall effect on the flow of current in a circuit.

2. How do you calculate equivalent resistance?

Equivalent resistance can be calculated using Ohm's Law, which states that resistance is equal to the voltage divided by the current. For a series circuit, the equivalent resistance is the sum of all individual resistances. For a parallel circuit, the equivalent resistance is equal to the reciprocal of the sum of the reciprocals of each individual resistance.

3. Why is it important to find the equivalent resistance in a circuit?

Finding the equivalent resistance in a circuit allows us to simplify complex networks of resistors and make calculations easier. It also helps us understand the overall effect of resistors in a circuit and how they affect the flow of current.

4. Can the equivalent resistance ever be lower than the lowest individual resistance?

Yes, in a parallel circuit, the equivalent resistance will always be lower than the lowest individual resistance. This is because the current has multiple paths to flow through, reducing the overall resistance.

5. What happens to the equivalent resistance when resistors are added in series or parallel?

In a series circuit, adding more resistors will increase the equivalent resistance. In a parallel circuit, adding more resistors will decrease the equivalent resistance. This is because resistors in series add up, while resistors in parallel have an inverse relationship.

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