Find the derivative of the function(Quotient rule)

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Homework Statement


Find the derivative of the function

<br /> y = (3-2x^3+x^6 )/x^9<br />

Homework Equations


Derivatives

The Attempt at a Solution


I have tried to use the quotient rule

and got to
<br /> -6x^11 + 6x^14 - 27x^8 + 18x ^24 - 9x ^14 / (x^9)^2 <br />
Which doesn't look close to the answer
<br /> -27/x^10 + 12/x^7 - 3 / x^4<br />
 
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Can you type in the steps to see what you have done so far? And you can as well use the product rule, it's the same.
I assume you have calculated ##(-9)(-2x^3)x^{8} = 18x^{24}## which is wrong. It has to be ##18x^{11}##.
 
Last edited:
fresh_42 said:
Can you type in the steps to see what you have done so far? And you can as well use the product rule, it's the same.
1st Part

(-6x^2+6x^5)(x^9) - ( 3-2x^3 + x^6) (9x^8)

2nd Part

-6x^11 + 6x^14 - (27x^8 - 18x^24 + 9x^14)

3rd Part

-6x^11+6x^14 - 27x^8 + 18x^24-9x^14

lol its hard to type math with itex
finished posting.
 
GustX said:
1st Part

(-6x^2+6x^5)(x^9) - ( 3-2x^3 + x^6) (9x^8)

2nd Part

-6x^11 + 6x^14 - (27x^8 - 18x^24 + 9x^14)

3rd Part

-6x^11+6x^14 - 27x^8 + 18x^24-9x^14

lol its hard to type math with itex
finished posting.
See my editorial above: ##x^3 \cdot x^8 = x^{11}## not ##x^{24}##.
 
fresh_42 said:
See my editorial above: ##x^3 \cdot x^8 = x^{11}## not ##x^{24}##.
Ah I see, I changed it up and it seems closer to the answer, but how do you transform from

(-27x^8+12x^11 - 3x^14)/ ((x^9)^2)

to( what do we do to the denominator)

-27/x^10 + 12/ x^7 - 3/ x^4

which is the answer
 
##(x^9)^2 = x^{18}## and ##\frac{1}{x^{18}}=x^{-18}##. So for example the first term is ## -27x^8 \cdot x^{-18}= -27x^{-10}=\frac{-27}{x^{10}}##.
 
fresh_42 said:
##(x^9)^2 = x^{18}## and ##\frac{1}{x^{18}}=x^{-18}##. So for example the first term is ## -27x^8 \cdot x^{-18}= -27x^{-10}=\frac{-27}{x^{10}}##.
lol I never woulda thought it that far
 
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