Find the Position of an Orbiting Spacecraft

In summary: I'm not sure where to start. Can you list those equations? They will relate the centriptal force to the angular velocity and other helpful things...
  • #1
Bluskyz
21
0

Homework Statement


Lets say that there is a small spacecraft (mass doesn't matter due to Earth's huge mass) orbiting Earth with a current distance from the center at 6,700,000 m. This whole problem is on a 2D plane with the spacecraft 's current position at (0,6700000). It's current velocity is at 8,000 m/s along the x-axis. I would like to know how to determine the spacecraft 's x and y coordinates at any point in time. I've made this problem only to satisfy my mathematical curiosity.


Homework Equations


Acceleration to Earth: F=GM/r^2
G= Gravitational Constant = 6.67384e-11 (m^3/kg*s^2)
Earth's Mass: 5.97e24


The Attempt at a Solution


I have tried multiple ways to get the solution and most of them ended up nowhere. So, please, can you explain how to get the answer? Thanks for your replies.
 
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  • #2
Bluskyz said:

Homework Statement


Lets say that there is a small spacecraft (mass doesn't matter due to Earth's huge mass) orbiting Earth with a current distance from the center at 6,700,000 m. This whole problem is on a 2D plane with the spacecraft 's current position at (0,6700000). It's current velocity is at 8,000 m/s along the x-axis. I would like to know how to determine the spacecraft 's x and y coordinates at any point in time. I've made this problem only to satisfy my mathematical curiosity.


Homework Equations


Acceleration to Earth: F=GM/r^2
G= Gravitational Constant = 6.67384e-11 (m^3/kg*s^2)
Earth's Mass: 5.97e24


The Attempt at a Solution


I have tried multiple ways to get the solution and most of them ended up nowhere. So, please, can you explain how to get the answer? Thanks for your replies.

Welcome to the PF.

You have correctly listed one of the Relevant Equations (gravitational force), but you are missing the equations for uniform circular motion (motion under the constant centripital acceleration of gravity).

Can you list those equations? They will relate the centriptal force to the angular velocity and other helpful things...

(If you aren't sure what they are, just Google the terms I used, or check wikipedia.org)
 
  • #3
Bluskyz said:

Homework Statement


Lets say that there is a small spacecraft (mass doesn't matter due to Earth's huge mass) orbiting Earth with a current distance from the center at 6,700,000 m. This whole problem is on a 2D plane with the spacecraft 's current position at (0,6700000). It's current velocity is at 8,000 m/s along the x-axis.
How are the axes set up relative to the earth? We need to know that before we can answer. If you set the axes up with the origin at the center of the Earth then the spacecraft is moving either directly toward or away from the earth. (And we don't know which because you did not give the direction of motion of the velocity.)

I would like to know how to determine the spacecraft 's x and y coordinates at any point in time. I've made this problem only to satisfy my mathematical curiosity.


Homework Equations


Acceleration to Earth: F=GM/r^2
G= Gravitational Constant = 6.67384e-11 (m^3/kg*s^2)
Earth's Mass: 5.97e24


The Attempt at a Solution


I have tried multiple ways to get the solution and most of them ended up nowhere. So, please, can you explain how to get the answer? Thanks for your replies.

Homework Statement


Yes, the acceleration, a (I wouldn't use "F" for acceleration) is equal to GM/r^2. Also [itex]a= dv/dt= d^2r/dt^2= GM/r^2[/itex]. We can integrate that using a method called "quadrature". Since v= dr/dt, by the chain rule, dv/dt= (dv/dr)(dr/t)= v dv/dr so that equation becomes v dv/dr= GM/r^2, a separable first order differential equation. Separating gives vdv= (GM/r^2)dr. Integrating, (1/2)v^2= -(GM/r)+ C. That can be written as (1/2)v^2+ GM/r= C which, if you multiply through by m, the mass of the ship, is "conservation of energy". Since v= dr/dt, we can solve (1/2)v^2= -(GM/r)+ C for v- [itex]v= \sqrt{2(C- (GM/r)}[/itex] and then integrate both sides of [itex]dx= \sqrt{2(C- GM/r)}[/itex].

That last equation will not be easy to integrate! It is, in fact, a simple example of type of integral called an "elliptic integral", so called precisely because it is involved in problems like this. And the more general problem, where the ship or other object is NOT moving directly on a line to or form the earth, typically gives elliptic orbits.

Homework Equations





The Attempt at a Solution

[/QUOTE]
 
  • #4
berkeman said:
Welcome to the PF.

You have correctly listed one of the Relevant Equations (gravitational force), but you are missing the equations for uniform circular motion (motion under the constant centripital acceleration of gravity).
Good point. I looked at the simple case- where the object is moving directly toward or away from the earth. "Uniform circular motion" is perhaps a bit more general. But general orbital motion is NOT "uniform circular motion". More common is elliptical motion where the speed depends on the distance from the earth.

Can you list those equations? They will relate the centriptal force to the angular velocity and other helpful things...

(If you aren't sure what they are, just Google the terms I used, or check wikipedia.org)
 
  • #5
The origin is centered on the center of Earth and the spacecraft is moving 8,000 m/s in the x direction. Initially, no motion on the y axis.

As for the uniform circular motion equations, don't you need to have it's rate of rotation around Earth ( the origin)? Like degrees per second
 
  • #6
HallsofIvy said:
Good point. I looked at the simple case- where the object is moving directly toward or away from the earth. "Uniform circular motion" is perhaps a bit more general. But general orbital motion is NOT "uniform circular motion". More common is elliptical motion where the speed depends on the distance from the earth.

Yes, I'm pretty sure it is elliptical motion, the spacecraft 's speed changes due to it's acceleration towards Earth given by GM/r^2.
 
  • #7
For a non-circular orbit the 'prediction problem' is not trivial. There are several mathematical methods available, most of which which involve solving a transcendental function. Investigate "The Kepler Problem" and "The Kepler Equation".

If you're keen on this topic I suggest picking up the the book "Fundamentals of Astrodynamics" by Bate, Mueller, and White. It's very inexpensive and covers the topic well and with plenty of examples and problems.
 
  • #8
gneill said:
For a non-circular orbit the 'prediction problem' is not trivial. There are several mathematical methods available, most of which which involve solving a transcendental function. Investigate "The Kepler Problem" and "The Kepler Equation".

If you're keen on this topic I suggest picking up the the book "Fundamentals of Astrodynamics" by Bate, Mueller, and White. It's very inexpensive and covers the topic well and with plenty of examples and problems.

Thanks for your reply. I have seen that book referenced many times on this subject so I think I'm going to get it. :)
 

Related to Find the Position of an Orbiting Spacecraft

1. What is the purpose of finding the position of an orbiting spacecraft?

Finding the position of an orbiting spacecraft is important for tracking and monitoring the spacecraft's location in space. This information is necessary for conducting experiments, conducting maneuvers, avoiding collisions, and communicating with the spacecraft.

2. How is the position of an orbiting spacecraft determined?

The position of an orbiting spacecraft is determined using various methods such as radar, optical tracking, and GPS. These methods involve sending signals to the spacecraft and measuring the time it takes for the signal to return, allowing scientists to calculate the spacecraft's distance and position.

3. What factors affect the position of an orbiting spacecraft?

The position of an orbiting spacecraft is affected by various factors such as the gravitational pull of celestial bodies, atmospheric drag, and solar radiation. These factors can cause the spacecraft to deviate from its intended orbit and require adjustments to be made.

4. Can the position of an orbiting spacecraft change over time?

Yes, the position of an orbiting spacecraft can change over time due to external factors such as gravitational pull and atmospheric drag. Additionally, spacecraft may also need to adjust their position for various purposes such as conducting experiments or avoiding collisions.

5. How do scientists use the position of an orbiting spacecraft for research?

Scientists use the position of an orbiting spacecraft for various research purposes such as studying the Earth's atmosphere, mapping the surface of other planets, and observing celestial bodies. The position of the spacecraft provides valuable information that helps scientists better understand our universe.

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