Finding inductance of a circuit

In summary, the author solves the problem of calculating inductance by deriving the inductance equation from Faraday's law. They use the phi (magnetic flux) = mmf/R (reluctance) equation to calculate the individual reluctance and put in L=N*phi/I. If you get the right answer, then you can begin to combine the equations, altough i don't see why there is a reason for that, your understanding of the subject is going to be poor if you are just to remember the specific equation, and not see the relations between reluctance, inductance, permanence, flux and magnetomotive force.
  • #1
dhruv.tara
46
0
NOTE: This is not a homework problem, so do not shift it.

The question is as follows, I am given a core having an air gap wounded by a coil, I am given area of core, gap. Length of core and gap. number of turns. Permeability of core and air gap and magnetic field in the core (I assume no leakage flux too) And I am required to find the inductance of the coil used.

I had a formula L = N^2*MuCore*MuO*AreaCore/lengthCore
I used it and got wrong answer. I realized that probably this formula was derived assuming no air gaps and that is why I got the answer wrongly.

I changed to the formula L=N*Flux/Current and got the answer correctly (in fact book I am following also uses the same approach)

But I realize that the formula L = N*Flux/Current was derived using the value of inductance written above (assuming that there is no air gap) So how does this time the new formula works?

According to me
L = N^2*MuCore*MuO*AreaCore*AreaGap/(LenCore*AGap + LGap*ACore)

(answer seems to be wrong using above formula too)

Any help is appreciated.
 
Engineering news on Phys.org
  • #2
Why not try to calculate the reluctance of the core and air-gap by them self, add them togther and then divide N^2 by the total reluctance. L=N^2/R or L= N^2*P where P(permanence)=1/R(reluctance)

Also fringing in the air gap should be taken into account.

If you get the right answer, then you can begin to combine the equations, altough i don't see why there is a reason for that, your understanding of the subject is going to be poor if you are just to remember the specific equation, and not see the relations between reluctance, inductance, permanence, flux and magnetomotive force.

There is also a possibility that the answer in the book is wrong.
 
  • #3
SirAskalot said:
Why not try to calculate the reluctance of the core and air-gap by them self, add them togther and then divide N^2 by the total reluctance. L=N^2/R or L= N^2*P where P(permanence)=1/R(reluctance)

Also fringing in the air gap should be taken into account.

If you get the right answer, then you can begin to combine the equations, altough i don't see why there is a reason for that, your understanding of the subject is going to be poor if you are just to remember the specific equation, and not see the relations between reluctance, inductance, permanence, flux and magnetomotive force.

There is also a possibility that the answer in the book is wrong.

Thank you for your reply, please help me a little further.

No I get the way you are mentioning. In fact my book also solves the problem in quite a similar fashion. What I don't get is that how we are able to use this equation because my current understanding of calculating inductances in such problems is as following:

phi (magnetic flux) = mmf/R(reluctance,total)
phi = NI*mu*area/length

then we use Faraday's law e=-nd(phi)/dt
so we get e = (n^2*mu*area/length)*d(I)/dt
now quantitatively we say that the coefficient of d(I)/dt in the above equation is the value of inductance.

Using this definition of inductance we derive L=N*phi/I (the form that you are probably using, and my book precisely uses)
Here we take phi as NI/RelucatanceTotal
phi = NI/(Rcore + Rgap)
we calculate individual reluctances and put in L=N*phi/I and get correct L.

But my problem with that solution is that the equation we are using L=N*phi/I is itself derived by considering that we have no air gaps or any such non-uniformity in the core.
(Because in deriving this formula we used L=N^2*mu*Area/Length which was derived for a uniform core)

Any help is appreciated.
 

Related to Finding inductance of a circuit

1. What is inductance?

Inductance is a measure of an object's ability to generate an electromotive force (emf) in response to a changing magnetic field. It is typically denoted by the letter L and is measured in units of henries (H).

2. How do you calculate the inductance of a circuit?

The inductance of a circuit can be calculated using the formula L = NΦ/I, where N is the number of turns in the coil, Φ is the magnetic flux through the coil, and I is the current flowing through the coil. Alternatively, it can also be calculated using the formula L = μN²A/l, where μ is the permeability of the material, N is the number of turns, A is the cross-sectional area of the coil, and l is the length of the coil.

3. Why is inductance important in circuit design?

Inductance plays a crucial role in circuit design as it affects the behavior of circuits in the presence of changing currents and magnetic fields. It can cause delays in the flow of current, filter out certain frequencies, and store energy in a circuit. Understanding inductance is important for designing efficient and stable circuits.

4. How does the inductance of a circuit affect its performance?

The inductance of a circuit can affect its performance in various ways. It can cause voltage spikes or delays in the flow of current, which can affect the accuracy and stability of a circuit. Additionally, the inductance of a circuit can also affect its resonant frequency, which is important for certain applications such as radio communication.

5. What factors affect the inductance of a circuit?

The inductance of a circuit is affected by several factors, including the number of turns in a coil, the material used in the coil, the shape and size of the coil, and the presence of other conductive materials nearby. The presence of iron or other ferromagnetic materials can also significantly increase the inductance of a circuit.

Similar threads

Replies
7
Views
2K
Replies
5
Views
813
  • Electrical Engineering
Replies
34
Views
2K
Replies
10
Views
1K
  • Electrical Engineering
Replies
10
Views
1K
  • Electrical Engineering
Replies
4
Views
1K
Replies
4
Views
1K
Replies
10
Views
579
  • Electrical Engineering
Replies
2
Views
941
Replies
27
Views
570
Back
Top