Finding the Inductor in an RL Circuit

[xswtxoj]

Homework Statement

I'm trying to find the inductor

RL Circuit:
Resistor (22Ω), Inductor , Function Generator
Resistance (Ω): 24.7 Ω 50

RL Circuit Half-Life: 64.00µs

RLC Circuit, Resonance:
Resistor (1000Ω), Inductor , Function Generator
Resistance (Ω): 1080 Ω 50

Capacitance: 11.63µf
Sine Wave Frequency at Resonance (voltage plots): 1.960 Hz
Sine Wave Frequency at Resonance (Lissajous figures): 550 Hz

Homework Equations

I'm not sure since there are so many on my lab sheet, but is it: t 1/2= 0.693(L/R)

The Attempt at a Solution

rearrange to (R* t 1/2)/0.693= L ?

 

[Nate810]

For the RL circuit, (22* 64.00µs)/0.693= 79.69µHFor the RLC Circuit, (1000* 11.63µf)/0.693= 8.22mH

 

[nlightner]

Yes, that is correct. The equation you have listed is the half-life equation for an RL circuit, where t 1/2 is the half-life, L is the inductance, and R is the resistance. Rearranging the equation to solve for L would give you the inductance value for the circuit. However, it is important to note that this equation assumes a purely inductive circuit. In a real circuit, there may be other factors such as capacitance that could affect the results. Therefore, it is important to take multiple measurements and use other equations to confirm the value of the inductance.