MHB Finding the Largest Root of a Polynomial Using Synthetic Division

  • Thread starter Thread starter karush
  • Start date Start date
  • Tags Tags
    Gre Root
AI Thread Summary
The polynomial \(x^3 - 3x^2 - 6x + 8\) has -2 as the smallest root. Using synthetic division, the polynomial is factored down to \(x^2 - 5x + 4\). This quadratic factors further into \((x - 1)(x - 4) = 0\). The roots of this quadratic are 1 and 4, making 4 the largest root. Therefore, the largest root of the polynomial is 4.
karush
Gold Member
MHB
Messages
3,240
Reaction score
5
$\tiny{GRE.al.06}$
For the polynomial $x^3-3x^2-6x+8\quad -2$ is the smallest root.
Find the largest root.
$a.\, -1 \quad b.\, 1 \quad c.\, 2 \quad d.\, 3 \quad e.\, 4$
Since -2 is a root then use synthetic division

$\begin{array}{r|rrrr}
-2&1&-3&-6&8\\
& & -2& 10&-8\\
\hline
&1& -5& 4&0
\end{array}$
then
$x^{2}- 5 x+4=(x-1)(x-4)=0$
so the largest factor is 4

hopefully
I doubt if it could done without some calculation maybe

 
Last edited:
Mathematics news on Phys.org
the largest root is 4
 
Thread 'Video on imaginary numbers and some queries'
Hi, I was watching the following video. I found some points confusing. Could you please help me to understand the gaps? Thanks, in advance! Question 1: Around 4:22, the video says the following. So for those mathematicians, negative numbers didn't exist. You could subtract, that is find the difference between two positive quantities, but you couldn't have a negative answer or negative coefficients. Mathematicians were so averse to negative numbers that there was no single quadratic...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...
Thread 'Imaginary Pythagoras'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...

Similar threads

Replies
2
Views
1K
Replies
8
Views
1K
Replies
3
Views
1K
Replies
2
Views
1K
Replies
6
Views
1K
Replies
2
Views
2K
Replies
2
Views
1K
Back
Top