- #1
Timebomb3750
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Finding a position vector...
A spaceship is traveling with acceleration a(t)=<e^(t) , t , sin2t>. At t=0, the spaceship was a origin r(0)=<0,0,0> and had an initial velocity of v(0)=<1,0,0> Find the position of the ship at t=pi
uhhh...
I figured I'd work backwards with the acceleration vector given to find the velocity and position vectors, then put the t=pi into the position vector I find.
So, v(t)=<e^(t) , (1/2)t^(2) , -(1/2)cos(2t)>
Then r(t)=<e^(t), (1/6)t^(3) , -(1/4)sin(2t)>
But this doesn't seem right to me because when I put in the given t=0 into my v(t), I get <1,0,-(1/2)> not the <1,0,0> like the problem says. I'm approaching this problem wrong, aren't I?
Homework Statement
A spaceship is traveling with acceleration a(t)=<e^(t) , t , sin2t>. At t=0, the spaceship was a origin r(0)=<0,0,0> and had an initial velocity of v(0)=<1,0,0> Find the position of the ship at t=pi
Homework Equations
uhhh...
The Attempt at a Solution
I figured I'd work backwards with the acceleration vector given to find the velocity and position vectors, then put the t=pi into the position vector I find.
So, v(t)=<e^(t) , (1/2)t^(2) , -(1/2)cos(2t)>
Then r(t)=<e^(t), (1/6)t^(3) , -(1/4)sin(2t)>
But this doesn't seem right to me because when I put in the given t=0 into my v(t), I get <1,0,-(1/2)> not the <1,0,0> like the problem says. I'm approaching this problem wrong, aren't I?