Finding Tower 2 Height to Achieve 3x Velocity

In summary, if the height of Tower 1 is d meters, then the height of Tower 2 needs to be 3*d meters for the object to reach triple the speed.
  • #1
Frankenstein19
56
0

Homework Statement


(I don't remember the EXACT problem because it was in an exam I took a few days ago but it was something like: If we drop the same object off of two towers, what does the height of Tower2 need to be if we want the object to fall is a velocity 3 times greater than the object falling off of tower1?

Homework Equations

The Attempt at a Solution


What I used was the vf^2 = vi^2 + 2ad and solved for d. (vf^2-vi^2)/2a = d and if vi = 0 then d=vf^2/2a

so the Height of tower 2 would have to be d=(3*vf^2)/2a, right?
 
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  • #2
Close.

The question you are answering is: if the height of tower #1 is d meters, then what height does tower #2 need to be for the mass to reach triple the speed?
 
  • #3
NascentOxygen said:
Close.

The question you are answering is: if the height of tower #1 is d meters, then what height does tower #2 need to be for the mass to reach triple the speed?
yes when it hits the ground
 
  • #4
Frankenstein19 said:

Homework Statement


(I don't remember the EXACT problem because it was in an exam I took a few days ago but it was something like: If we drop the same object off of two towers, what does the height of Tower2 need to be if we want the object to fall is a velocity 3 times greater than the object falling off of tower1?

Homework Equations

The Attempt at a Solution


What I used was the vf^2 = vi^2 + 2ad and solved for d. (vf^2-vi^2)/2a = d and if vi = 0 then d=vf^2/2a

so the Height of tower 2 would have to be d=(3*vf^2)/2a, right?
If vf1 is the velocity of something dropped off Tower 1, then the velocity of something dropped off Tower 2, vf2 = 3 * vf1. That's how you write triple the first speed.
 
  • #5
Frankenstein19 said:
yes when it hits the ground
So, what is the answer?
 

What is "Finding Tower 2 Height to Achieve 3x Velocity"?

"Finding Tower 2 Height to Achieve 3x Velocity" is a scientific experiment or calculation that determines the necessary height of a tower in order to achieve three times the velocity of a falling object.

Why is it important to know the height of the tower?

Knowing the height of the tower is important for various reasons. It can help in designing and constructing buildings or structures with specific velocity requirements. It can also aid in predicting the trajectory and impact of falling objects, which is crucial for safety and disaster prevention.

What factors affect the accuracy of this calculation?

The accuracy of this calculation can be affected by various factors such as air resistance, gravitational pull, and the initial velocity of the falling object. Other factors like wind speed and direction, temperature, and atmospheric pressure may also play a role in the final result.

What is the formula for "Finding Tower 2 Height to Achieve 3x Velocity"?

The formula for this calculation is h = (v²/2g) x (3² + 1), where h is the height of the tower, v is the initial velocity of the falling object, and g is the acceleration due to gravity (9.8 m/s²).

Can this calculation be used for any falling object?

Yes, this calculation can be applied to any falling object as long as the initial velocity and acceleration due to gravity are known. However, it is important to note that other factors such as air resistance may affect the final result.

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