Fluid mechanics- Dimensional analysis

In summary, the statement regarding the drag force on a car can be rewritten in terms of two independent non-dimensional groups, (Dρ/µ^2) and (ρVL/µ). To calculate the airspeed in the wind tunnel for dynamic similarity, we can use the non-dimensional group (ρVL/µ) and equate the Reynolds number for the full-scale car to the Reynolds number for the 1/4-scale model. The airspeed in the wind tunnel must be 0.24 times the airspeed of the full-scale car. To calculate the drag force on the full-size car, we can use the equation D_f = (ρ_m / ρ_f) * (µ_f / µ_m)^2 *
  • #1
andyb1990
34
0

Homework Statement



The drag force F on a car depends upon its speed V, length L, the density ρ of the air
and the dynamic viscosity of the air µ . Show that this statement regarding five
physical quantities can be re-written in terms of two independent non-dimensional
groups. Preferably using the method of sequential elimination of dimensions, find two
appropriate non-dimensional groups

I have got my two non- dimensional groups as (Dρ/µ^2) and (ρVL/µ)

FOR THE SECOND PART (BELOW) I AM UNSURE ON HOW TO ACHIEVE THE AIRSPEED IN THE TUNNEL

A car being developed for the Le Mans 24 Hour Endurance Race is to have a top speed
of 230 mph assuming an air density of 1.2kg/m^3 and dynamic viscosity of 1.9 x 10^-5
Pa.s. Tests carried out on a 1/4-scale model car in a pressurized and cooled wind tunnel
in which the air density is 5kg/m^3 and the dynamic viscosity is 1.1 x 10^-5
Pa.s give a drag force of 469 N. What must be the airspeed in the wind tunnel for dynamic similarity (at top speed for the full-size car)? Calculate the drag force on the full size car
and the power needed to run at top speed.


Homework Equations





The Attempt at a Solution



for part a i have the two non dimensional groups shown above and for part (b) I have worked out the drag force using the equation

Df= (ρm/ρf)* (μf/μm)^2 * Dm

(f= full scale, m= model)

It would be of great help if someone could help me understand how to calculate the windspeed and power needed?
 
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  • #2




To calculate the airspeed in the wind tunnel, we can use the non-dimensional group (ρVL/µ) that you have already found. This group represents the ratio of inertial forces (ρVL) to viscous forces (µ) and is known as the Reynolds number (Re). We can equate the Reynolds number for the full-scale car (Re_f) to the Reynolds number for the 1/4-scale model (Re_m):

Re_f = Re_m

ρ_f * V_f * L_f / µ_f = ρ_m * V_m * L_m / µ_m

Since the length and dynamic viscosity of the air remain constant in both cases, we can simplify the equation to:

V_f / V_m = ρ_m / ρ_f

Substituting in the given values for air density, we can solve for V_f:

V_f = (1.2 kg/m^3) / (5 kg/m^3) * V_m

V_f = 0.24 * V_m

Therefore, the airspeed in the wind tunnel must be 0.24 times the airspeed of the full-scale car, or approximately 55.2 mph.

To calculate the drag force on the full-size car, we can use the equation you have already found:

D_f = (ρ_m / ρ_f) * (µ_f / µ_m)^2 * D_m

Substituting in the given values, we get:

D_f = (5 kg/m^3 / 1.2 kg/m^3) * (1.9 x 10^-5 Pa.s / 1.1 x 10^-5 Pa.s)^2 * 469 N

D_f = 1665 N

To calculate the power needed to run at top speed, we can use the equation:

P = F * V

Where P is power, F is force, and V is velocity. Substituting in the values for drag force and velocity (230 mph or 102.7 m/s), we get:

P = 1665 N * 102.7 m/s

P = 171,100 watts or 171.1 kW
 

1. What is the purpose of dimensional analysis in fluid mechanics?

Dimensional analysis is used to relate physical quantities to each other in order to understand their behavior and predict their values. In fluid mechanics, it is particularly useful for determining the relationship between different variables such as pressure, velocity, and density.

2. How is dimensional analysis applied in fluid mechanics?

Dimensional analysis involves breaking down a complex problem into simpler components and determining the relationships between the variables using basic physical principles. This allows for the creation of dimensionless numbers, which can then be used to analyze and compare different systems.

3. What are the benefits of using dimensional analysis in fluid mechanics?

Dimensional analysis helps to simplify complex problems and identify key variables that affect the behavior of fluids. It also allows for the creation of dimensionless numbers, which can be used to compare systems and make predictions without the need for complex calculations.

4. What are some common dimensionless numbers used in fluid mechanics?

Some common dimensionless numbers used in fluid mechanics include the Reynolds number, Froude number, and Mach number. These numbers describe the relative importance of different physical effects and can help determine the behavior of fluids in different systems.

5. Can dimensional analysis be used to solve any problem in fluid mechanics?

No, dimensional analysis is not a foolproof method for solving all problems in fluid mechanics. It is most effective for problems that involve similar physical quantities and can be reduced to a few key variables. In some cases, additional experimental data may be needed to validate the results obtained through dimensional analysis.

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