Force due to Solar Radiation and Gravity

In summary: You need to find an expression for the force of solar radiation on the particle, set it equal to the gravitational force, and solve for r. Can you do that?In summary, we are given information about a small spherical particle located a distance R from the Sun and we need to find the value of r for which the particle is in equilibrium between gravitational force and solar radiation. Using the equations F(g)=Gm1m2/r2 and mass density=mass/volume, we can calculate the force of solar radiation and set it equal to the gravitational force. After solving for r, we get a value of 790238.5, but this calculation does not take into account the solar constant S. Therefore, the final
  • #1
Mnemonic
21
0

Homework Statement


Consider a small, spherical particle of radius r located in space a distance R = 3.75 × 1011-m from the Sun. Assume the particle has a perfectly absorbing surface and a mass density of ρ = 3.8-g/cm3. Use S = 214 W/m2 as the value of the solar intensity at the location of the particle. Calculate the value of r for which the particle is in equilibrium between the gravitational force and the force exerted by solar radiation. The mass of the Sun is 2.0 × 1030-kg.

Homework Equations


F(g)=Gm1m2/r2

mass of particle equals mass density/Volume=3800/(4/3*Pi*r2)

F(Solar)=C*S*I/c
where C=1 due to complete absorption, S equals cross-sectional area (Pi*[rSUP]2[/SUP]), c equals speed of light

The Attempt at a Solution


F(Solar)=F(g)

Pi*r2/3e8=6.67e-11*2e30*3800/(3.75e11*4/3*Pi*r3)

r=790238.5

Have I used the right Solar radiation equation?

Does this look right?
 
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  • #2
Mnemonic said:

Homework Statement


Consider a small, spherical particle of radius r located in space a distance R = 3.75 × 1011-m from the Sun. Assume the particle has a perfectly absorbing surface and a mass density of ρ = 3.8-g/cm3. Use S = 214 W/m2 as the value of the solar intensity at the location of the particle. Calculate the value of r for which the particle is in equilibrium between the gravitational force and the force exerted by solar radiation. The mass of the Sun is 2.0 × 1030-kg.

Homework Equations


F(g)=Gm1m2/r2

mass of particle equals mass density/Volume=3800/(4/3*Pi*r2)
Check that formula. Does mass really get smaller as the volume of the material gets larger?
F(Solar)=C*S*I/c
where C=1 due to complete absorption, S equals cross-sectional area (Pi*[rSUP]2[/SUP]), c equals speed of light

The Attempt at a Solution


F(Solar)=F(g)

Pi*r2/3e8=6.67e-11*2e30*3800/(3.75e11*4/3*Pi*r3)

r=790238.5

Have I used the right Solar radiation equation?

Does this look right?
Nope. Besides the issue with the mass expression noted above, I don't see where the solar constant S is involved in your calculation.
 

1. What is force due to solar radiation?

The force due to solar radiation is the pressure exerted by sunlight on an object. It is caused by the transfer of momentum from photons, or particles of light, to the surface of the object. This force is also known as solar radiation pressure.

2. How does solar radiation affect objects in space?

Solar radiation can affect objects in space by exerting a force that can cause them to move or change their trajectory. This force is particularly significant for small, lightweight objects such as spacecraft or particles in the solar system.

3. How does the force due to solar radiation compare to the force of gravity?

The force due to solar radiation is much weaker than the force of gravity. While gravity depends on the mass and distance between two objects, solar radiation pressure is affected by the size and reflectivity of the object. In most cases, the force of gravity is much stronger than the force of solar radiation.

4. Can force due to solar radiation be used for propulsion?

Yes, force due to solar radiation can be used for propulsion in space. This is known as solar sailing, where a spacecraft uses the force of solar radiation on a large reflective sail to generate thrust and propel itself through space.

5. How does the Earth's atmosphere affect force due to solar radiation?

The Earth's atmosphere can reduce the force of solar radiation on objects in space by absorbing or scattering some of the incoming sunlight. This is why solar radiation pressure is more significant in the vacuum of space compared to objects within the Earth's atmosphere.

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