How Does Projectile Motion Affect a Ball Thrown Upward from a Building?

In summary, a ball thrown vertically upward from a tall building with an initial velocity of 15 m/s will reach a maximum height of 11.48 m after 1.5306 seconds. At this point, the ball will have a velocity of 0 m/s and an acceleration of -9.8 m/s^2.
  • #1
VaioZ
19
0

Homework Statement


You throw a ball vertically upward from the roof of a tall building. The ball leaves your hand at a point even with the roof railing with an upward speed of 15.0 m/s; the ball is then in free fall. On its way back down, it just misses the railing.
Find (a) the position and velocity of the ball 1.0 s and 4.0 s after leaving your hand;
(b) the velocity when the ball is 5.0 m above the railing;
(b.1) How long will the ball reach 5 m
(c) the maximum height reached and the time at which it is reached; and
(d) the acceleration of the ball when it is at its maximum height.

Homework Equations


Freefall equation like Vf=Vo-gt and etc

The Attempt at a Solution


T at 1
a.) ΔY = (15 m/s)(1 s) - (1/2)(9.8 m/s^2)(1 s)^2
ΔY = 10.1 m

T at 4
ΔY = -18.4 m

V at 1
Vf = (15 m/s) - (9.8 m/s^2)(1)
= 5.2 m/s

V at 4
Vf = -24.2 m/s

b.) Vf^2 = Vi^2 - 2gΔy
Vf^2 = (15 m/s)^2 - (2)(9.8 m/s^2)(5 m)
Vf^2 = 11.27 m/s

b.1) (11.27 m/s) = (15 m/s) - (9.8^2)(t)
t = 0.38

5 m = (15 m/s)(t) - (1/2)(9.8 m/s^2)(t)
t = 2.68

I'm a bit confuse here I got 2 different answer in this part. Really need a big help here

c.) a = Δv/Δt -> t = Δv/a -> t = (15 m/s)/(9.8 m/s^2)
tmax = 1.5306

Δymax = (15 m/s)(1.5306 s) - (1/2)(9.8 m/s^2)(1.5306 s)^2
y = 11.48

d.) The answer is -9.8 m/s^2 right? Constant?
 
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  • #2
For question b.1) you wrote 5=15t-9,8*0.5t while it should be 5=15t-9.8*0.5T^2
 
  • #3
Sobhan said:
For question b.1) you wrote 5=15t-9,8*0.5t while it should be 5=15t-9.8*0.5T^2

lol I am such a stupid one

is my c.) and d.) right?
 
  • #4
VaioZ said:
lol I am such a stupid one

is my c.) and d.) right?
Yes, c and d are right.
 

What is the freefall body problem?

The freefall body problem is a mathematical model used to describe the motion of an object in freefall under the influence of gravity. It takes into account the object's initial position, velocity, and acceleration due to gravity.

What is the difference between freefall and regular motion?

In regular motion, an object may experience various forces that cause it to change its speed and direction. In freefall, the only force acting on the object is gravity, causing it to accelerate towards the ground at a constant rate.

How is the freefall body problem solved?

The freefall body problem is typically solved using the equations of motion, such as the kinematic equations, and incorporating the acceleration due to gravity. These equations can be solved using calculus or numerical methods.

What factors affect the motion of a freefalling object?

The motion of a freefalling object is affected by its initial position, velocity, and mass. It is also affected by external factors such as air resistance and the presence of other forces.

Is the freefall body problem applicable to real-world situations?

Yes, the freefall body problem is applicable to real-world situations, such as the motion of objects falling from a height or the trajectory of a projectile. However, it may not accurately account for factors like air resistance, which can affect the motion of an object in freefall.

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