The equations you quote are for motion in one straight line. What is the geometric relationship between the a and vi quoted above?DracoMalfoy said:
- Vi: 10m/s
- a: -9.8m/s^2
Make a sketchDracoMalfoy said:is thrown off of a building in the +x direction
i made a hideous sketch lol. I am not sure how to do this when I am not given an angleBvU said:Make a sketch
Oh, and: show your work in detail. I can't reconstruct ##\approx## 5 m no matter how hard I try
DracoMalfoy said:i have projectile motion equations but the question doesn't come with an angle so I got confused
The angle is implied.DracoMalfoy said:i have projectile motion equations but the question doesn't come with an angle so I got confused
The initial velocity of a ball thrown off of a building can be calculated using the equation v = √(2gh), where v is the initial velocity, g is the acceleration due to gravity (9.8 m/s²), and h is the height of the building.
The maximum height reached by a ball thrown off of a building can be calculated using the equation h = (v₀²sin²θ)/(2g), where h is the maximum height, v₀ is the initial velocity, θ is the angle of the throw, and g is the acceleration due to gravity.
Air resistance can affect the motion of a ball thrown off of a building by slowing down its velocity and causing it to reach a lower maximum height. This is because air resistance creates a force that acts opposite to the direction of motion, reducing the overall acceleration of the ball.
According to the equations of kinematics, the mass of the ball does not affect its motion when thrown off of a building. However, in real-world scenarios, the mass of the ball may have a small impact on its velocity and trajectory due to air resistance and other external factors.
The final velocity of a ball thrown off of a building can be calculated using the equation v = v₀ + at, where v is the final velocity, v₀ is the initial velocity, a is the acceleration due to gravity, and t is the time the ball has been in motion.