Gauss Row Operations: Solving by Hand?

In summary, the conversation discusses a method for solving equations by hand using an algorithm. The process involves dividing the first row by the number in the first column, then using that result to create zeros in the subsequent rows. This process is repeated for each column until the matrix is in upper triangular form. If a pivot is 0 or all numbers below it are 0, the process is unable to continue.
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I am just interested is there anyway to solve these through a specific method by hand. I know that you can produce an algorithm so that you can solve these into upper triangle form but is there a way to do it by hand other than by inspection.
 
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  • #2
I've always done them "by hand" (I learned all this in the years "B.C."- Before Calculators!). The 'algorithm' I preferred was : Divide the first row by whatever number was in "first row, first column"(the "pivot"). Now look at each succeeding row. You can get a 0 there by "multiply that new first row by the number in first column, nth row and subtract from the nth row". Once you've done that your first column has a 1 at the "pivot" and 0's below. Now move on to the second column. Divide the second row by whatever number is in the "pivot" (second column second row). For every succeeding row (you can ignore the first row and first column) multiply the second row by the number in "second column nth row" and subtract that from the nth row. Once you done that the second column has a 1 in the "pivot" and 0s below. Work your way across the columns that way.

Of course, if, at any time, the "pivot" is 0 so that you CAN'T divide the row by it, you will need to swap that row with a lower row. If, at any time, a "pivot" and all numbers below it in that column are 0, you are DONE. You CAN'T get that matrix is "upper triangular" form.
 
  • #3


There are several methods for solving systems of linear equations by hand, including Gauss-Jordan elimination and Gaussian elimination. These methods involve using row operations to transform the system into an upper triangular form, making it easier to solve for the variables. While it is possible to solve systems of equations by hand through inspection, it is not a reliable or efficient method. Using a systematic approach, such as Gauss row operations, is more accurate and allows for larger systems of equations to be solved. Additionally, using row operations allows for a clear and organized process, making it easier to catch any mistakes. So, while it is possible to solve systems of equations by hand without using a specific method, it is not recommended.
 

Related to Gauss Row Operations: Solving by Hand?

1. What are Gauss row operations?

Gauss row operations are a method used to solve systems of linear equations by transforming the equations into a simpler form. This is done by using elementary row operations, such as multiplying a row by a constant or adding a multiple of one row to another.

2. How are Gauss row operations used to solve equations by hand?

In order to solve equations by hand using Gauss row operations, the equations must first be written in matrix form. Then, the matrix is manipulated using the elementary row operations until it is in row-echelon form. The solutions can then be determined by back substitution.

3. Can Gauss row operations be used to solve any type of system of equations?

Yes, Gauss row operations can be used to solve any system of linear equations, regardless of the number of variables or equations. However, the process may become more complex as the number of variables and equations increase.

4. What are the advantages of solving equations by hand using Gauss row operations?

Solving equations by hand using Gauss row operations allows for a better understanding of the underlying mathematics and concepts. It also provides a more accurate solution compared to using calculators or computer programs.

5. Are there any limitations to using Gauss row operations?

One limitation of using Gauss row operations is that it can be time-consuming and tedious for larger systems of equations. It also requires a good understanding of matrix operations and may not always be the most efficient method for solving equations.

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