Gaussian functional integral with constant operator

In summary, a Gaussian functional integral with constant operator is a mathematical expression used in quantum field theory to calculate the probability of a quantum field configuration. The constant operator represents the potential energy of the field and allows for the inclusion of interactions in the integral. This type of integral differs from a regular Gaussian integral in that it involves an infinite number of variables and is used in the context of quantum field theory. The Gaussian weight function is crucial in ensuring the convergence of the integral and is often chosen for its simplicity. This type of integral is used in physics to understand and predict the behavior of particles and fields in quantum systems.
  • #1
Einj
470
59
Hello everyone. What it the result for a Gaussian functional integral when the "matrix" is nothing but a number? Mathematically speaking is the following true?

$$
\int \mathcal{D}\phi e^{-\int d^3k f(k) |\phi(k)|^2}\propto \left(f(k)\right)^{-1/2}
$$

Here ##f(k)## is just a function of k, not derivatives or operators etc... I'm asking this because in principle we should have a determinant of the "matrix" and I don't know if what I wrote is correct.
Thanks!
 
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  • #2


Hello there!

It is true that the result for a Gaussian functional integral when the "matrix" is a number is given by the equation you have provided. This is known as the Wick rotation or Wick's theorem, and it is a powerful tool in calculating Gaussian integrals in quantum field theory.

To understand why this is true, let's break down the equation. The integral on the left-hand side, ##\int \mathcal{D}\phi e^{-\int d^3k f(k) |\phi(k)|^2}##, is known as a functional integral. It is a generalization of the usual integral, but instead of integrating over a variable, we are integrating over a function. In quantum field theory, we use functional integrals to calculate the probability amplitudes for different field configurations.

Now, the function ##f(k)## is just a number, as you have mentioned. This means that the integral is essentially a product of integrals over each value of k. And since the function is just a number, we can take it outside of the integral. This gives us the equation:

$$
\int \mathcal{D}\phi e^{-\int d^3k f(k) |\phi(k)|^2} = \int \mathcal{D}\phi e^{-f(k)\int d^3k |\phi(k)|^2}
$$

Now, we can use the fact that the integral of a Gaussian function is given by ##\sqrt{\frac{\pi}{f(k)}}##. This is a well-known result in mathematics, and you can find its derivation in many textbooks. Applying this result to our equation, we get:

$$
\int \mathcal{D}\phi e^{-f(k)\int d^3k |\phi(k)|^2} = \prod_k \sqrt{\frac{\pi}{f(k)}} = \left(f(k)\right)^{-1/2}
$$

So, to answer your question, yes, your equation is correct. There is no need for a determinant of the "matrix" in this case, as it is just a number. I hope this helps clarify things for you. Keep exploring and asking questions!
 

Related to Gaussian functional integral with constant operator

1. What is a Gaussian functional integral with constant operator?

A Gaussian functional integral with constant operator is a mathematical expression used in quantum field theory to calculate the probability of a quantum field configuration. It involves integrating over all possible field configurations, with a Gaussian weight function and a constant operator acting on the fields.

2. What is the significance of the constant operator in a Gaussian functional integral?

The constant operator in a Gaussian functional integral represents the potential energy of the quantum field. It is used to account for interactions between the field and other particles or fields in the system. Without this operator, the integral would only account for the kinetic energy of the field.

3. How is a Gaussian functional integral with constant operator different from a regular Gaussian integral?

A regular Gaussian integral is a standard integral over a Gaussian function, while a Gaussian functional integral with constant operator involves integrating over an infinite number of variables (the field configurations) and includes the constant operator. The latter is also used in the context of quantum field theory, while regular Gaussian integrals are more commonly used in statistics and probability.

4. What is the importance of the Gaussian weight function in a Gaussian functional integral with constant operator?

The Gaussian weight function is used to weight each field configuration in the integral, giving more weight to configurations with lower energy. This ensures that the integral converges and allows for the calculation of meaningful results. Additionally, the Gaussian weight function is often chosen for its simplicity and mathematical convenience.

5. How is a Gaussian functional integral with constant operator used in physics?

A Gaussian functional integral with constant operator is used in physics to calculate the probability of a particular quantum field configuration. This is important in understanding the behavior and interactions of particles and fields in quantum systems. It is also used in theoretical models to make predictions about physical phenomena, such as in the study of phase transitions and critical phenomena.

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