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Do you understand the derivation from Gauss' law? (You can also just add up all the contributions to the electric field at a point. Same result.)nivamani Rajbongshi said:
Gauss's law is all about the electric flux, isn't it. So the line of force of a charge travel to infinity, so at a point on which we will calculate e.field intensity may lie at infinite distance, also in this derivation we do calculate the derivation by taking 0 rad angle between E and ds, i.e. all the lines of force that we take for calculation are may be perpendicular to that sheet so for those lines of forces the point on which we r going to calculate E doesn't depend on the distance of the point from the surface of the sheet. Am i right?? I don't think...so, Please explain me clearly.Doc Al said:
Forget about finding the field "at infinity". The point of this model is that the dimensions of the plate are huge compared to the distance from the plate, so that we can treat the plate as effectively infinite (and thus ignore any effects from being near an edge).nivamani Rajbongshi said:
The field at any point is perpendicular to the sheet. Thus the only parts of the Gaussian surface that will have a flux is the end pieces.nivamani Rajbongshi said:
Since the amount of charge enclosed -- and thus the flux -- doesn't change with distance from the plate, we can conclude that the field does not depend on that distance.nivamani Rajbongshi said:
Gauss's Law is a fundamental principle in electromagnetism that describes the relationship between electric fields and electric charges. It states that the electric flux through a closed surface is equal to the total enclosed charge divided by the permittivity of free space. This law can be applied to determine the electric field intensity on non-conducting sheets by considering the direction and magnitude of the electric field lines passing through the sheet.
To calculate the electric field intensity on a non-conducting sheet, we first need to determine the charge enclosed by the sheet. This can be done by finding the total charge on one side of the sheet and multiplying it by the sheet's area. Then, we can use Gauss's Law to find the electric field intensity by dividing the enclosed charge by the permittivity of free space and multiplying by the sheet's area.
Yes, Gauss's Law can be applied to any shape of non-conducting sheet as long as the sheet is a closed surface and the electric field lines pass perpendicularly through the sheet.
The electric field intensity on a non-conducting sheet is different from that on a conducting sheet because of the difference in charge distribution. On a non-conducting sheet, the charge is evenly distributed throughout the sheet, whereas on a conducting sheet, the charge accumulates on the surface. This results in a different electric field intensity distribution on the two types of sheets.
Gauss's Law and the electric field intensity on non-conducting sheets have various applications, including calculating the electric field intensity in capacitors and determining the electric field distribution in electronic devices. It is also used in industries such as telecommunications and power generation to optimize and control electric fields for efficient operation.
