In other words, the state is diagonal in the basis formed by the apparatus states. In summary, the process of quantum measurement involves a specific physical model where a quantum system is measured using two additional systems, an apparatus and an environment. This process involves a dynamical evolution and discarding of the environment, resulting in a state where the apparatus states are independent of the input state. This is necessary for the process to constitute a measurement. Additionally, in this context, "coherence" refers to the off-diagonal elements of the density matrix, which have leaked away into the environment during the dynamical evolution.
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Danny Boy
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The following, regarding quantum measurement, is stated in the paper "Limitation on the amount of accessible information in a quantum channel" :

"Our discussion of measurement will be based on a specific physical model of measurement, to which we now turn. Suppose we have a quantum system ##Q## with an initial state ##\rho^{(Q)}##. The measurement process will involve two additional quantum systems an apparatus system ##A## and an environment system ##E##. The systems ##A## and ##E## are initially in a joint state ##\rho_{0}^{(AE)}##, so that the overall initial state of everything is ##\rho^{(AEQ)} = \rho_{0}^{(AE)} \otimes \rho^{(Q)} ##.

The measurement process proceeds in two successive stages :

1. A dynamical evolution including interactions among ##A, E## and ##Q## represented by a unitary operator ##U##:

$$\rho^{(AEQ) } \rightarrow \hat{\rho}^{(AEQ) } = U\rho^{(AEQ) } U^{\dagger} $$

2. Discarding of the environment, represented by a partial trace over the system ##E##:

$$\hat{\rho}^{(AEQ)} \rightarrow \hat{\rho}^{(AQ)} = \text{Tr} _{E}\hat{\rho}^{(AEQ)}$$

For the process to constitute a measurement, we require that after these two stages, the state ##\hat{\rho}^{(AQ)}## be of the following form:

$$\hat{\rho}^{(AQ) } = \sum_a P(a) |\phi_{a}^{(A) } \rangle \langle \phi_{a}^{(A) }| \otimes w_{a}^{(Q) }~~~~~~~~~~~~(*) $$

Where the states ##|\phi_{a}^{(A) }## are a fixed orthogonal set of apparatus states, independent of the input state ##\rho^{(Q) }##.

Questions:

1. Why does the system have to be in state ##(*)## for the process to constitute a measurement? I

2. It is further stated "Coherences between different measurement outcomes do not remain in the joint state of systems ##A## and ##Q##. Any such coherences have leaked away into the environment during the dynamical evolution." How would you define/interpret the word "coherence" in this context?

Thanks for any assistance.
 
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Danny Boy said:
The following, regarding quantum measurement, is stated in the paper "Limitation on the amount of accessible information in a quantum channel"
This link doesn't work for me.

Danny Boy said:
1. Why does the system have to be in state ##(*)## for the process to constitute a measurement?
I have only skimmed the passage but what about turning this around: modify the state in different ways and think about the consequences. For example, introduce more indices.

Danny Boy said:
2. It is further stated "Coherences between different measurement outcomes do not remain in the joint state of systems ##A## and ##Q##. Any such coherences have leaked away into the environment during the dynamical evolution." How would you define/interpret the word "coherence" in this context?
In open quantum dynamics, the term "coherences" often refers to the off-diagonal elements of the density matrix. (The on-diagonal elements are called "populations".)

In your example, it refers to the fact that only one index appears in each term of the sum.
 
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1. What is a general quantum measurement?

A general quantum measurement is a process in which the state of a quantum system is observed or measured, resulting in a change of the system's state. It involves interacting with the system in a way that extracts information about its properties.

2. How are general quantum measurements different from classical measurements?

General quantum measurements differ from classical measurements in that they can involve superposition and entanglement, two fundamental principles of quantum mechanics. This allows for a wider range of possible outcomes and can result in unpredictable or probabilistic results.

3. What is the significance of general quantum measurements in quantum computing?

General quantum measurements are essential in quantum computing as they allow for the manipulation and extraction of information from quantum systems, which are the building blocks of quantum computers. Without general quantum measurements, quantum computers would not be able to perform calculations and solve complex problems.

4. Can general quantum measurements be reversed?

In most cases, general quantum measurements are irreversible. This means that once a measurement is made, the quantum state of the system cannot be restored to its original state. However, there are certain cases where reversible measurements can be made, such as in quantum error correction protocols.

5. How are general quantum measurements used in quantum cryptography?

General quantum measurements play a crucial role in quantum cryptography, particularly in the key distribution process. By measuring the quantum state of a photon, the intended recipient can verify the authenticity of the transmission and ensure that no one has intercepted or tampered with the message. This is made possible by the principles of superposition and entanglement in quantum measurements.

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