- #1
Ofinns
- 13
- 0
Hi,
For a harmonic oscillator in 3D the energy level becomes En = hw(n+3/2) (Note: h = h_bar and n = nx+ny+nz) If I then want the 1st excited state it could be (1,0,0), (0,1,0) and (0,0,1) for x, y and z.
But what happens if for example y has a different value from the beginning? Like this: V(x,y,z) = 1/2mw2(x2+4y2+z2) and for this decide the energy level AND degeneracy for the 1st excited state. I can only find simple examples when x, y and z are equal and 1.
Best regards
For a harmonic oscillator in 3D the energy level becomes En = hw(n+3/2) (Note: h = h_bar and n = nx+ny+nz) If I then want the 1st excited state it could be (1,0,0), (0,1,0) and (0,0,1) for x, y and z.
But what happens if for example y has a different value from the beginning? Like this: V(x,y,z) = 1/2mw2(x2+4y2+z2) and for this decide the energy level AND degeneracy for the 1st excited state. I can only find simple examples when x, y and z are equal and 1.
Best regards