Having trouble understanding the relationship between these expressions

In summary, the conversation discusses the equation √MgL/m = L/t and the problem of measuring the free-fall acceleration on a small planet using a wire and a suspended mass. The second section clarifies that the equality does not come from √MgL/m but rather from the wave speed equation v = √T/u and the distance over time equation L/t. It also mentions that the second section is just an algebraic rearrangement of the second equation in the first section.
  • #1
coldjeanz
22
0
38v5P.png


I understand everything up until:

√MgL/m = L/t

Why is that equal to L/t?

I also don't understand this either:

U8IiJ.png


This is the problem itself however I don't feel it's that important since I am trying to figure out how they are arriving at their conclusions.

An astronaut on a small planet wishes to measure the local value of the free-fall acceleration by timing pulses traveling down a wire that has an object of large mass suspended from it. Assume a wire has a mass of 4.10 g and a length of 1.60 m and that a 3.00 kg object is suspended from it. A pulse requires 43.6 ms to traverse the length of the wire. Calculate g of planet from these data. (You may ignore the mass of the wire when calculating the tension in it.)
 
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  • #2
They are not saying that the last equality follows from something about [itex]\sqrt{MgL/m}[/itex], but rather that the wave speed [itex]v[/itex] is equal to both [itex]\sqrt{T/u}[/itex] AND [itex]L / t[/itex] (since speed is just distance divided by time).

The second section is just an algebraic rearrangement of the second equation in the first section.
 
  • #3
Yeah okay that went through my head for a split second but I couldn't find that in my book so I didn't know where they pulled it from. Thank you!
 

Related to Having trouble understanding the relationship between these expressions

1. What are some common expressions that people have trouble understanding?

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