Heuristic for simple two-photon scattering problems

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In summary, the conversation discusses two-photon scattering and the use of phase difference in calculating power and photon count at different output ports. It is suggested that a similar logic can be applied to calculate probabilities for different events, such as seeing two photons at a certain port or seeing one photon at one port and another at a different port. This method may also be applicable for three photons and multiple inputs.
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Swamp Thing
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I'm afraid this question is going to be a bit hand-wavy, but I'm hoping for a way of thinking about two-photon scattering that would be helpful to a beginner but also give correct results.

The starting point is that, for two photons in SPDC and other similar cases, the phase difference is a uniform superpositiion from 0 to ##2\pi##.

Next, we consider scattering through a system that has 2 inputs and N outputs. This could be as simple as a beam splitter or something more complex, but let's say we know the amplitudes and phases to go from any input to any output.

Now we excite the two inputs with two coherent waves and vary their phase difference ##\Delta\phi## from 0 to ##2\pi##. For each phase difference value, we can find the power going to each output port. If we integrate that over ##\Delta\phi## from 0 to ##2\pi## we can get the expectation of the power, which is the expectation of the photon count at that port up to a constant.

My question is, isn't there a similar logic that says if we integrate "something" over 0 to ##2\pi## we can get the probability of seeing two photons at a certain port, and if we integrate something else, we can get the probability of seeing one photon "here" and another "there".

Hope that makes sense... o_O

And if that is possible, then how about three photons into three inputs -- can we double-integrate something over the phase difference between input A and B, as well as input B and C, to get the probability of seeing 2 photons over here and one over there?
 
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Swamp Thing said:
Now we excite the two inputs with two coherent waves and vary their phase difference Δϕ from 0 to 2π. For each phase difference value, we can find the power going to each output port. If we integrate that over Δϕ from 0 to 2π we can get the expectation of the power, which is the expectation of the photon count at that port up to a constant.

In the last sentence in the quote, I mean that the same expectation of photon count, that we work out using coherent states as a test case, would also apply to non-coherent photons (Fock state) sent into the inputs of the same scattering problem, because non-coherent pairs have a Δϕ that is a superposition over 0 to 2π. And in a similar way, I'd like to derive probabilities for other classes of events as well.
 

Related to Heuristic for simple two-photon scattering problems

1. What is a heuristic for simple two-photon scattering problems?

A heuristic for simple two-photon scattering problems is a problem-solving approach that involves using educated guesses or intuitive reasoning to find a solution. It is often used in physics to simplify complex problems and find approximate solutions.

2. How does a heuristic approach differ from a traditional problem-solving method?

A heuristic approach differs from a traditional problem-solving method in that it does not follow a rigid step-by-step process but instead relies on intuition and educated guesses. It is also more flexible and allows for more creativity in finding solutions.

3. What are the advantages of using a heuristic for simple two-photon scattering problems?

One advantage of using a heuristic for simple two-photon scattering problems is that it can help simplify complex problems and find approximate solutions. It can also be more time-efficient and allow for more creativity in finding solutions.

4. Are there any limitations to using a heuristic for simple two-photon scattering problems?

Yes, there are limitations to using a heuristic for simple two-photon scattering problems. Since it relies on intuition and educated guesses, the solutions obtained may not always be accurate or optimal. It may also be difficult to determine when to stop using a heuristic and switch to a traditional problem-solving method.

5. Can a heuristic approach be applied to other scientific problems?

Yes, a heuristic approach can be applied to other scientific problems. It is commonly used in fields such as physics, chemistry, and computer science to simplify complex problems and find approximate solutions. However, it may not be suitable for all types of problems and should be used with caution.

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