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santa
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solve in R
[tex](x^2+2)^{1/3}+(4x^2+3x-2)^{1/3}=(3x^2+x+5)^{1/3}+(2x^2+2x-5)^{1/3}[/tex]
[tex](x^2+2)^{1/3}+(4x^2+3x-2)^{1/3}=(3x^2+x+5)^{1/3}+(2x^2+2x-5)^{1/3}[/tex]
santa said:solve in R
[tex](x^2+2)^{1/3}+(4x^2+3x-2)^{1/3}=(3x^2+x+5)^{1/3}+(2x^2+2x-5)^{1/3}[/tex]
Are you sure thatVietDao29 said:Then, your original equation will becomes:
[tex]\sqrt[3]{\alpha} + \sqrt[3]{\gamma - \alpha} = \sqrt[3]{\beta} + \sqrt[3]{\gamma - \beta}[/tex]
When [tex]\gamma = 0[/tex], both sides equal 0
CompuChip said:Are you sure that
[tex]\sqrt[3]{\alpha} + \sqrt[3]{-\alpha} = \sqrt[3]{\alpha - \alpha} = 0[/tex]
CompuChip said:Taking x = 0 the formula becomes
[tex]\sqrt[3]{2} + \sqrt[3]{-2} = \sqrt[3]{5} + \sqrt[3]{-5}[/tex]
which, numerically, is something like
[tex]1.89 + 1.09 i = 2.56 + 1.48 i[/tex]
santa said:good work but
let [tex]$ \sqrt[3]{x^2+2}=a, \ \sqrt[3]{4x^2+3x-2}=b, \ \sqrt[3]{3x^2+x+5}=c, \ \sqrt[3]{2x^2+2x-5}=d.[/tex]
these may be help
VietDao29 said:On graphing it, I can see there are actually 4 solutions.. Not sure how you can obtain another 2 solutions.
NateTG said:[tex]\alpha=\beta[/tex]
and
[tex]\gamma=\alpha + \beta[/tex]
Are obviously solutions - no idea if that gets you anything.
Edit: Looks like those are all imaginary solutions.
solve in R
[tex](x^2+2)^{1/3}+(4x^2+3x-2)^{1/3}=(3x^2+x+5)^{1/3}+(2x^2+2x-5)^{1/3}[/tex]
The general process for solving cubic equations in R involves using the "solve" function, which takes in the coefficients of the cubic equation as arguments. R then finds the roots of the equation and returns them as a list of complex numbers. However, it is important to note that this method may not work for all cubic equations, especially those with complex roots.
Yes, R is capable of solving cubic equations with real coefficients. However, as mentioned before, the "solve" function may not work for all cubic equations, so it is important to check the validity of the solutions returned.
Yes, there are alternative methods for solving cubic equations in R, such as using the "polyroot" function or manually using the quadratic formula for solving the depressed cubic equation. These methods may be more reliable for certain types of cubic equations.
Yes, R has various functions and packages, such as "curve" and "ggplot2", that allow you to graph cubic equations. You can also use the "plot" function to graph the solutions of the cubic equation as points on a graph.
You can check the validity of your solutions by plugging them back into the original cubic equation and seeing if it satisfies the equation. You can also use the "all.equal" function to check if the solutions are close enough to the correct value.