How Do You Calculate Display Readings from Pressure in a Cream-Filled Silo?

In summary, the conversation discusses a 150 m^3 silo used to store cream with a density of 850 kg m^-3. An electronic pressure sensor is mounted 0.6 m up from the base of the tank and a 0 to 100% display is used to indicate the level. The display can be calibrated with a constant offset to account for the extra fluid below the sensor. The conversation also mentions deriving an equation to relate the display reading to the sensor pressure and finding the offset needed for the 0.6 m mounting height. The conversation then poses a question about the height of the silo needed for the display to read 100% when filled with water instead of cream. The equations used in the attempt
  • #1
joe98
27
0

Homework Statement



A 150 m^3 silo(cylinder) (12 m high) is used to store cream (density 850 kg m-3). An electronic pressure sensor (measures gauge pressure) is mounted 0.6 m up from the base of the tank, and a 0 to 100% display is used to indicate the level. It is not possible to sense
the level once it is below the sensor, but the display can be calibrated with a constant
offset to account for this extra fluid (for example, the sensor can show 10% when
there is no pressure). Derive an equation to relate the display reading (in %) to the
sensor pressure. What offset should be used on the display to account for the 0.6 m
mounting height? If water is used instead of cream, how high must the silo be in
order for the display (calibrated for cream) to read 100% when the silo is full?

Homework Equations



P=F/A
P=ρ+ρgh
ρ=m/v
Q=Av

The Attempt at a Solution


I have no idea where to start where can I start with ok

m=ρV=850/150=5.7kg

I am not sure how to derive an equation to relate the display reading (in %) to the
sensor pressure.

Any clues guys

cheers
 
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  • #2
would I be able to use Bernoullies principle on this question?
 

Related to How Do You Calculate Display Readings from Pressure in a Cream-Filled Silo?

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