- #1
Tom McCurdy
- 1,020
- 1
taking derivitive of 2xy^2+xy=y
split up to using product rule
[tex] 2x----2 [/tex]
[tex] y^2---2y\frac{dy}{dx} [/tex]
[tex]4yx\frac{dy}{dx}+2y^2+y+x\frac{dy}{dx}=\frac{dy}{dx}[/tex]
[tex] \frac{dy}{dx} (4x+x-1)=-2y^2-y [/tex]
[tex] \frac{dy}{dx}= \frac{-2y^2-y}{4xy+x-1} [/tex]
i am trying to figure out the slope of the equation when y-1
am i doing all this for nothing?
split up to using product rule
[tex] 2x----2 [/tex]
[tex] y^2---2y\frac{dy}{dx} [/tex]
[tex]4yx\frac{dy}{dx}+2y^2+y+x\frac{dy}{dx}=\frac{dy}{dx}[/tex]
[tex] \frac{dy}{dx} (4x+x-1)=-2y^2-y [/tex]
[tex] \frac{dy}{dx}= \frac{-2y^2-y}{4xy+x-1} [/tex]
i am trying to figure out the slope of the equation when y-1
am i doing all this for nothing?
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