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jbriggs444
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So you now admit that your earlier understanding that they are equal is incorrect, are we agreed on that much?Kaneki123 said:Unequal...Why?
So you now admit that your earlier understanding that they are equal is incorrect, are we agreed on that much?Kaneki123 said:Unequal...Why?
Have you ever tried pushing water uphill with a rake?jbriggs444 said:So you now admit that your earlier understanding that they are equal is incorrect, are we agreed on that much?
Can you show us where it is stated that tension has to be the same as weight?Kaneki123 said:Can you please elaborate?
See post #30.Kaneki123 said:Unequal...Why?
Yes I agree...Does this mean that the mass need not neccessarily put as much force on string as its weight...But if it puts as much force as its weight, it will be at rest...If it puts force lesser than its weight, then the reactional tension will be of THAT force and thus the weight will dominate causing the mass to accelerate...?jbriggs444 said:So you now admit that your earlier understanding that they are equal is incorrect, are we agreed on that much?
If you put your trust in flowery words then the result can be anything. Just stick with the Maths and the answer will come rolling out. It was about five hundred years ago that we first found that out and I recommend you get up to date with your analysis of such a simple system.Kaneki123 said:Yes I agree...Does this mean that the mass need not neccessarily put as much force on string as its weight...But if it puts as much force as its weight, it will be at rest...If it puts force lesser than its weight, then the reactional tension will be of THAT force and thus the weight will dominate causing the mass to accelerate...?
That all seems correct and in accord with what many people have been saying.Kaneki123 said:Yes I agree...Does this mean that the mass need not neccessarily put as much force on string as its weight...But if it puts as much force as its weight, it will be at rest...If it puts force lesser than its weight, then the reactional tension will be of THAT force and thus the weight will dominate causing the mass to accelerate...?
This is one of those consequences of Newton's Laws that seems counterintuitive until you explore it a little: a body can apply a force greater or less than its weight. Consider that if I place a five pound weight on your head, it applies less force than if I drop it ten feet onto you head.Kaneki123 said:Yes I agree...Does this mean that the mass need not neccessarily put as much force on string as its weight...
This is another place where your intuition about motion will lead you astray until you internalize the laws. The first law says that when the sum of the forces is zero, a body remains at rest if it was already at rest and remains in uniform motion if it was already in motion. SO if the tension in the string equals the weight, the dangling mass will not accelerate, but it can be at rest or moving uniformly. (jbriggs444 acknowledged that, but I wanted to take the opportunity to emphasize it. It will be very useful if you continue your study of Newton's laws.)But if it puts as much force as its weight, it will be at rest...
Your understanding is not correct....According to my understanding, ALL of the forces (represented by arrows) in the diagram are equal in magnitude, whether the body M is accelerating or not...Correct me with some explanation...
Just a couple of points to consider:Kaneki123 said:Thank You guys for your replies and sticking with me...