How extract phase angle from reflectance using Kramers-Kronig

In summary: The conversation discusses the use of Kramers-Kronig relations to calculate the complex refractive index from spectral reflectance data. The results were not appropriate and it was suspected that the phase angle was calculated incorrectly. The Matlab code used for the calculation is also mentioned. There is a discussion about the discrepancy between the calculated n and k values and the expected values for the material being measured. Possible solutions such as spectrum extrapolation, adding a phi(0) value, and normalization are mentioned for improving the accuracy of the results. Further research and discussion is needed for finding a suitable solution.
  • #1
shayu
6
0
I try to extract optical constants (complex refractive index) from the spetral reflectance data - R(omiga), the common method is using Kramers-Kronig relations to calculate the Phase information of the reflection - Psi(omiga), then according to the normal reflection coefficients, the complex refractive index can be extracted. But in the practice, I found the results didn't look appropriate, so i guess the phase angle-Phi(omiga) may be calculated uncorrectly, and can not find the mistake for a long time. So, indeed need your expert advice and help, if you have the right tool, can you calculate the results for me? thank you.
Reply for me also can mail to : shayu296@gmail.com , I will be appreciate for your advice.

the main calculate formation as listed below:
Phi.png

nk.png


The reflectance data is from 200nm to 2500nm measured by spectrophotometer, as listed below.
View attachment Reflectance data.xls

Why the calculated phase angle have positive and negtive values both? that is also the reason why k have positve and negtive values both. I thought maybe the wavelength region is not wide enough, but from some refrences it should can be calculated. Is there something Wrong in my code? but i think it is right ... I am confused by the Kramers-Kronig calculation...:cry:

Matlab code:
Code:
function[Phi temp]=refphase2(R)
% %2011-07-20
% Phase angle calculation using Kramers-Kronig relation.
% R - measured reflectance data, column 1 is wavelength, column 2 is reflectance
% Phi is the phase angle
% Ref:      Kramers-Kronig Transform and Applications.pdf
%           Stern, F. 1963. Elementary Optical Properties of Solids. Solid State Phys. vol15:327-340.
% google books: Frederick Seitz,Solid State Physics: Advances in Research and Applications, P337 

tic;
wavlen0=length(R);  %length of wavelength
wav0=1e7./R(:,1);   %wavelength->wavenumber   nm -> cm-1 
ref0=R(:,2);   %reflectance
%interplation 
wav=[wav0(1):2*sign(wav0(end)-wav0(1)):wav0(end)]';  %new interval 0.25cm-1
ref=interp1(wav0,ref0,wav,'spline');  %reflectance interplation
wavlen=length(ref);

Phi=zeros(wavlen0,1);  %phase angle initialization
temp=[];
for i=1:wavlen0-1
 % integration using discrete summing
    intsum=0;  
 g=i
 for j=1:wavlen-1
%%%%% if 'wav(j)=wav0(g)'  then 'wav(j+1)' replace 'wav(j)', to aviod 'log(0)=-inf'
        if wav(j)==wav0(g)
            temp(j,i)=(log(ref(j+1))-log(ref(j)))*log(abs((wav(j+1)-wav0(g))/(wav(j)+wav0(g)))); 
        else
            temp(j,i)=(log(ref(j+1))-log(ref(j)))*log(abs((wav(j)-wav0(g))/(wav(j)+wav0(g))));
        end
    intsum=intsum+temp(j,i);
    end
    Phi(i)=(1/2*pi)*intsum;
end
Phi(wavlen0)=Phi(wavlen0-1);
Phi(1)=2*Phi(2)-Phi(3);
toc
end
 
Last edited:
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  • #2
I don't understand much of this, however, looking at your excel file, it appears to me as if n and k are interchanged as the graph of k has a dispersive shape and n an absorptive one. I suppose, there is somehow a factor of pi/2 missing in your phase angle.
 
  • #3
shayu;3433558 [ATTACH=full said:
37720[/ATTACH]

Btw. Shouldn't there be a cos(phi) in the formula for n?
 
  • #4
DrDu said:
Btw. Shouldn't there be a cos(phi) in the formula for n?

the formula has no problem, it can be found in many reference...
 
  • #5
DrDu said:
I don't understand much of this, however, looking at your excel file, it appears to me as if n and k are interchanged as the graph of k has a dispersive shape and n an absorptive one. I suppose, there is somehow a factor of pi/2 missing in your phase angle.

complex refractive index always in the form n^=n+i*k, for the real part n is the refractive index, imaginery part k is known as absorptive index (absoption coefficient alpha=4*pi*k/lambda).
how to say the calculated k has a dispersive shape and n an absorptive one? the measured material is Cr2O3, commonly its n should be greater than 1, and k is great than 0, attached picture is the n&k of some meterial (SubPc). why the calculated k is less than 0 and n is less than 1?
 

Attachments

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  • #6
Recent days, i have found some references about the phase extraction as so far, some important steps may include:
(i) spectrum extrapolation (equivalent to delta_Phi approximation); (Ref. 1)
(ii) the phase 'Phi' should add with a ' phi(0) ', which has the value ' -pi+abs(delta) for abs(delta)<<1' ; (Ref.2)
(iii) phase retrieval problem - 'convergence' , should be removed by normalization and 'zeros' Blaschke factor; (Ref.3)
But i also doubt about the phase calculation problem, does the three different steps mentioned above have some consistency??

Any one to discuss these problems? Hope you to give me some advise... :bugeye:Ref:
[1]
P. O. Nilsson and L. Munkby. Investigation of errors in the Kramers-Kronig analysis of reflectance data. ZEITSCHRIFT FÜR PHYSIK B CONDENSED MATTER. Volume 10, Number 3, pp.290-298.
[2]
Nash P.L.; Bell R.J.; Alexander R.. On the Kramers-Kronig relation for the phase spectrum. Journal of Modern Optics, Volume 42, Number 9, September 1995 , pp. 1837-1842(6).
[3]
P. Grosse and V. Offermann. Analysis of reflectance data using the Kramers-Kronig Relations. APPLIED PHYSICS A: MATERIALS SCIENCE & PROCESSING. Volume 52, Number 2, pp.138-144.
 
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  • #7
I already proposed to add phi(0) with seems to be approximately +-pi/2 in your problem.
When analyzing e.g. NMR spectra, the programs usually allow you to change the phase offset continuously so as to make k positive on the whole axis. (n is not bound to be >1, it can also be smaller 1 in some regions).
 
  • #8
DrDu said:
I already proposed to add phi(0) with seems to be approximately +-pi/2 in your problem.
When analyzing e.g. NMR spectra, the programs usually allow you to change the phase offset continuously so as to make k positive on the whole axis. (n is not bound to be >1, it can also be smaller 1 in some regions).

many thanks for you, DuDu, your suggestion about ' adding a phi(0) ' does make sense, and it matched with one of the references, but that phi(0) is '-pi+abs(delta)', and the 'delta' is depending on the material which is measured, and it is unknow to me. So, if follow your suggestion, i should find a suitable physical assumption for add a phi(0)=+-pi/2, could you tell my why +-pi/2 but +-pi in detail?
 
  • #9
It is just a guess given that your data to my eye seem to have more a dispersive lineshape in the case of k and an absorptive form in the case of n (and a factor of pi/2 would reverse this).
Now just a speculation: Wouldn't be that factor phi(0) be best which would maximize the integral of k over frequency (eventually weighed with some power of frequency)?
 

1. What is the Kramers-Kronig relation?

The Kramers-Kronig relation is a mathematical relationship between the real and imaginary parts of a complex function. It states that the real part of a complex function is related to the imaginary part through integration and vice versa.

2. How is the Kramers-Kronig relation used in reflectance analysis?

In reflectance analysis, the Kramers-Kronig relation is used to extract the phase angle from the measured reflectance data. By applying this relation, the phase angle can be calculated from the real and imaginary parts of the complex reflectance function.

3. Why is it important to extract the phase angle from reflectance data?

The phase angle extracted from reflectance data can provide information about the optical properties of a material, such as the refractive index and absorption coefficient. This information is critical for understanding the behavior of light in different materials and can be useful in various scientific and technological applications.

4. How is the phase angle extracted from reflectance using the Kramers-Kronig relation?

The phase angle can be extracted from reflectance data using the Kramers-Kronig relation by first calculating the real and imaginary parts of the complex reflectance function. Then, the integral of the real part is taken over a specific wavelength range to obtain the imaginary part. Finally, the phase angle is calculated from the ratio of the imaginary and real parts.

5. Are there any limitations to using the Kramers-Kronig relation for phase angle extraction?

While the Kramers-Kronig relation is a powerful tool for extracting the phase angle from reflectance data, it does have some limitations. It assumes that the reflectance is a smooth and continuous function, and can be affected by noise in the data. Additionally, the accuracy of the extracted phase angle can be influenced by the wavelength range used for the integration.

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