How far does each can slide on the table?

In summary, the question asks how far paint cans, weighing 46N each, will slide down a 24 degree ramp at a constant speed of 3.4 m/s before reaching a table made of the same material as the ramp. Using the equations mgsin(x) and KE = mv²/2, it is determined that the cans will slide approximately 1.5 meters on the table. This assumes that the cans are given some initial speed before being placed on the ramp. Additionally, the forces of friction and gravity must be equal in order for the cans to maintain a constant velocity down the incline.
  • #1
kashiark
210
0

Homework Statement


In a hardware store, paint cans, which weigh 46N each, are trasnported from storage to the back of the paint department by placing them on a 24 degree ramp. The cans slide down the ramp at a constant speed of 3.4 m/s onto a table made of the same material as the ramp. How far does each can slide on the table?


Homework Equations


mgsin(x) = component of gravity in the same dimension as the incline on which the object sits
KE = mv²/2
ΔKE = Fd


The Attempt at a Solution


46sin(24) ≈ 18.7
-(46/9.8)(3.4)²/2 = -18.7d
d ≈ 1.5
My problem is if the friction force were equivalent to the force of gravity down the incline, the the paint cans would never move.
 
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  • #2


The frictional force and the force propelling the cans down the incline must be equal, as the cans are moving at a constantly velocity, so all forces are in equilibrium.

I think we're assuming the cans are originally given some speed to begin with, and aren't placed on the ramp stationary, as the question does say it has a velocity.
 
  • #3


I would like to clarify that the calculations provided in the attempt at a solution are incorrect. The correct equations for this scenario would be:

1. The net force acting on the paint can:
Fnet = mgsin(x) - μmgcos(x)

2. Equating this net force to the mass times acceleration (since the can is moving at a constant speed, the acceleration is 0):
mg(sin(x) - μcos(x)) = 0

3. Solving for μ (the coefficient of friction between the ramp and the can):
μ = tan(x)

4. Now, using the formula for work done by a force (W = Fd), we can calculate the distance each can slides on the table:
Fd = μmgcos(x)d
d = μmgcos(x)/F

5. Plugging in the values given in the problem, we get:
d = (tan(24))(46)(9.8)(cos(24))/(46)
d ≈ 1.5m

Therefore, each can will slide approximately 1.5 meters on the table. It is important to note that this is an ideal scenario and does not take into account factors such as air resistance and imperfections in the surface of the ramp and table. These factors may slightly affect the distance the cans slide.
 

Related to How far does each can slide on the table?

1. How does the weight of the can affect its sliding distance?

The weight of the can does not have a significant impact on its sliding distance. The main factors that affect the sliding distance are the surface of the table and the force applied to the can.

2. Is there a difference in sliding distance between different types of cans?

The type of can does not have a significant impact on its sliding distance. As long as the surface and force are consistent, the sliding distance should be similar for all types of cans.

3. What is the maximum sliding distance a can can reach on a table?

The maximum sliding distance a can can reach on a table is dependent on the surface and force applied. In a controlled experiment, the maximum sliding distance can be determined by gradually increasing the force until the can reaches a point where it no longer slides.

4. Does the material of the table affect the sliding distance?

The material of the table can affect the sliding distance. A smooth surface, such as glass, will likely result in a longer sliding distance compared to a rough surface, such as wood. This is due to the amount of friction between the can and the surface.

5. Can factors such as humidity or temperature affect the sliding distance of a can?

Humidity and temperature can potentially affect the sliding distance of a can. Higher humidity can create a more slippery surface, resulting in a longer sliding distance. Similarly, higher temperatures can also decrease the friction between the can and the surface, resulting in a longer sliding distance.

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